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Harlamova29_29 [7]
3 years ago
9

What happens when the electron moves from the first energy level to the second energy level?

Chemistry
2 answers:
STatiana [176]3 years ago
5 0
If an electron moves up from the first orbit to the higher energy levels, energy will be absorbed by the electron itself and no emission line produced.
But if it moves from the orbits 6,5,4 and 3 to orbit 2, energy will be released by the electron and different emission lines wll be produced.
ki77a [65]3 years ago
4 0

Your answer is: Energy is absorbed by the atom.

this is correct hope it helps:)

You might be interested in
When 2 moles of NH3(g) react with N2O(g) to form N2(g) and H2O(g) according to the following equation, 880 kJ of energy are evol
Naily [24]

Answer:

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

Explanation:

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system. The total enthalpy of the reaction (\Delta H) comes out to be negative.

According to reaction, 2 moles of ammonia when reacts with 3 moles of  nitrous oxide to give 4 moles of nitrogen gas and 3 moles of water vapor, along with release of 880 kJ of heat energy.

Since, heat is evolved during the course of reaction which means that reaction is an example of Exothermic reaction.

2NH_3(g)+3N_2O(g)\rightarrow 4N_2(g)+3H_2O(g),\Delta H=-880 kJ

The reaction is an exothermic reaction .

The value of q is -880 kilo Joules.

5 0
3 years ago
Weighted averages, help please
yarga [219]

Answer:

Average atomic mass of Cl = 35.48 amu

Average atomic mass of B  = 10.8  amu

Average atomic mass of Ag  = 107.96 amu

Explanation:

1)

Given data:

Abundance of Cl-35 = 75.8%

Abundance of Cl-37 = 24.2%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (75.8×35)+(24.2×37) /100

Average atomic mass =  2653 + 895.4 / 100

Average atomic mass  = 3548.4 / 100

Average atomic mass  = 35.48 amu

2)

Given data:

Abundance of B-10 = 19.8%

Abundance of B-11 = 80.2%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (19.8×10)+(80.2×11) /100

Average atomic mass = 198  +882.2  / 100

Average atomic mass  = 1080.2 / 100

Average atomic mass  = 10.8  amu

3)

Given data:

Abundance of Ag-107 = 52%

Abundance of Ag-109 = 48%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (52×107)+(48×109) /100

Average atomic mass =  5564 +5232  / 100

Average atomic mass  = 10796 / 100

Average atomic mass  = 107.96 amu

4 0
3 years ago
What is the name of GaF3?
Ksivusya [100]

Answer:

Gallium III fluoride (pretty sure)

Explanation:

3 0
3 years ago
12) A 17.92 g sample of copper was submerged in water, and the volume reading rose by 2.00 mL. What is the density of the copper
emmasim [6.3K]

Hey there!:

Mass = 17.92 g

Volume = 2.00 mL

Density =  ??

Therefore:

D = m / V

D = 17.92 / 2.00

D = 8.96 g/mL

Hope this helps!

3 0
3 years ago
Na
tensa zangetsu [6.8K]

Answer:

Argon is a noble gas

Hope this helps

5 0
2 years ago
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