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Harlamova29_29 [7]
3 years ago
9

What happens when the electron moves from the first energy level to the second energy level?

Chemistry
2 answers:
STatiana [176]3 years ago
5 0
If an electron moves up from the first orbit to the higher energy levels, energy will be absorbed by the electron itself and no emission line produced.
But if it moves from the orbits 6,5,4 and 3 to orbit 2, energy will be released by the electron and different emission lines wll be produced.
ki77a [65]3 years ago
4 0

Your answer is: Energy is absorbed by the atom.

this is correct hope it helps:)

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# of protons = 48 <br><br> Cadmium <br> Titanium <br> Oxygen <br> Krypton
Dafna11 [192]

Answer:

Cadmium +p= 48

Titanium p=22

Oxygen p=8

Krypton p=36

So the answer is Cadmium which has #48 protons

Explanation:

7 0
2 years ago
A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 0.70

Putting values in above equation, we get:

0.70=-\log[H^+]

[H^+]=10^{-0.70}=0.199M

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

Hence, the volume of concentrated solution required is 9.95 mL

6 0
2 years ago
PLZ HURRY
Oxana [17]

Answer:

C

Explanation:

3 0
3 years ago
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viva [34]

Answer:

fog

Explanation:

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Llana [10]

Explanation:

I think the answer is this for a better check mass- mass ratio in stoichiometry lesson

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2 years ago
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