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TiliK225 [7]
4 years ago
10

A chunk of pure silver weighs 20.0 g. What is its volume? Silver has a density of 10.49 g/cm cubed. Use unit analysis, NOT the D

ensity formula.
Chemistry
1 answer:
julia-pushkina [17]4 years ago
8 0

Answer: 1.91cm3

Explanation:

10.49g of silver dissolves is 1cm3 of solution.

Therefore 20g of silver will dissolve in = 20/10.49 = 1.91cm3 of the solution.

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Explanation:

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A

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If the ka of a monoprotic weak acid is 5.4 × 10-6, what is the ph of a 0.14 m solution of this acid?
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pH = 2.1

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\left\begin{array}{cccccc}\text{R}&HA(aq)&\rightleftharpoons&H^{+}(aq) &+ &A^{-}(aq)\\\text{I} & 0.14 \; \text{M} & &\\\text{C}&-x \; \text{M}& &+x \; \text{M} & & +x \; \text{M}\\E & (0.14 - x)\; \text{M} & & x \; \text{M} & &\+x \; \text{M}\end{array}\right

By definition, (all concentrations are under equilibrium condition)

\left\begin{array}{ccc}K_{a}&=&[H^{+}] \cdot [A^{-}] / [HA]\\&=&x^{2} /(0.14 - x)\end{array}\right

It is given that

K_a = 5.4 \cdot 10^{-6}

Equating and simplifying the two expressions gives a quadratic equation; solve the equation for x gives:

x^2 = 5.4 \cdot 10^{-6} \cdot (14 - x) \\x^2 + 5.4 \cdot 10^{-6} \cdot 14 \cdot x - 5.4 \cdot 10^{-6} \cdot 14 = 0 \\x = 0.0087 \; \text{M} \; (x \ge 0)

The pH of a solutions equals the opposite of the logarithm of its proton concentration to base 10; thus for this particular solution

\text{pH} = -\text{ln(}[H^{+}]\text{)} / \text{ln(}10\text{)} = 2.1

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4 years ago
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