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3 years ago

2x — 7y = 24 What is the answer for this equation?

Mathematics

2 answers:

Nesterboy [21]3 years ago

8 0

Answer:

Step-by-step explanation:

Move 2x to the right side of the equation and it becomes -7y= -2x + 24 and then divide by -7 and then it becomes y = 2/7 x -24/7

zubka84 [21]3 years ago

4 0

Answer:

2x - 7y = 24

2x - 24 = 7y

7y = 2x - 24

y = (2x - 24)/7

= 2/7x - 24/7

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Find the equation of the line that is perpendicular to 4 x + 3 y = 5 and goes through the point (3, –3)

Allisa [31]

Step-by-step explanation:

the line equation

y = ax + b

gives us slope (a) and y-interception (b).

4x + 3y = 5

3y = -4x + 5

y = -4/3 × x + 5/3

the slope of the original line is therefore -4/3.

a perpendicular slope flips x and y upside-down and flips the sign.

so, the perpendicular slope of -4/3 is 3/4.

the desired line looks like

y = 3/4 × x + b

b we get by using the given point and its coordinates :

-3 = 3/4 × 3 + b = 9/4 + b

-12/4 = 9/4 + b

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y = 3/4 × x - 21/4

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2 years ago

4pi/3 find the exact trigonometric ratios for the angle whose radian measue is given

bulgar [2K]

Answer:

All trigonometric ratios.

Step-by-step explanation:

We have to find all the trigonometric ratios.

Given:

$\theta = \dfrac{4\pi}{3} = \pi + \dfrac{\pi}{3}$

Formula:

$\sin(\pi +x) = -\sin(x)\\\cos(\pi +x) = -\cos(x)$

$\sin(\pi + \dfrac{\pi}{3}) = -\sin(\dfrac{\pi}{3}) = -\dfrac{\sqrt{3}}{2}$

$\cos ((\pi + \dfrac{\pi}{3})) = -\cos(\dfrac{\pi}{3}) = -\dfrac{1}{2}$

Formula:

$\tan\theta =\dfrac{\sin\theta}{\cos\theta}\\\cot\theta = \dfrac{1}{\tan\theta}\\\sec\theta = \dfrac{1}{\cos\theta}\\\csc\theta = \dfrac{1}{\sin\theta}$

$\tan(\pi + \dfrac{\pi}{3})= \dfrac{\sin(\pi + \dfrac{\pi}{3})}{\cos(\pi + \dfrac{\pi}{3})}\\\\\tan(\pi + \dfrac{\pi}{3}) = \dfrac{\frac{-\sqrt{3}}{2}}{\frac{-1}{2}} = \sqrt{3}$

$\cot(\pi + \dfrac{\pi}{3}) = \dfrac{1}{\tan(\pi + \dfrac{\pi}{3})} = \dfrac{1}{\sqrt{3}}$

$\sec(\pi + \dfrac{\pi}{3}) = \dfrac{1}{\cos(\pi + \dfrac{\pi}{3})} = -2$

$\csc(\pi + \dfrac{\pi}{3}) = \dfrac{1}{\sin(\pi + \dfrac{\pi}{3})} = -\dfrac{2}{\sqrt{3}}$

8 0

3 years ago