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Ad libitum [116K]
3 years ago
9

You have a 100 ml stock solution of 100 mg/ml ampicillin in deionized water. You want to make 30 ml of 25 mg/ml ampicillin in de

ionized water. How many milliliters (ml) of 17 ampicillin stock and how many of deion ized water are needed to make this stock solution? atealk
Chemistry
1 answer:
Georgia [21]3 years ago
3 0

Explanation:

Volume of the stock solution is V_{1} = ?

Initial concentration of ampicillin is M_{1} = 100 mg/ml

Final volume (V_{2}) = 30 ml

Final concentration of  ampicillin (M_{2}) = 25 mg/ml

Therefore, calculate the volume of given stock as follows.

              M_{1} \times V_{1} = M_{2} \times V_{2}

Now, putting the given values into the above formula as follows.

            M_{1} \times V_{1} = M_{2} \times V_{2}

            100 mg/ml \times V_{1} = 25 g/ml \times 30 ml    

                   V_{1} = 7.5 ml

Now, we will calculate the volume of water added into it as follows.

            Volume of water added = V_{2} - V_{1}

                                                  = 30 ml - 7.5 ml

                                                  = 22.5 ml

Thus, we can conclude that required solution is 22.5 ml of deionized water.

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