Answer:
The equilibrium concentration of NO in the gas mixture should be 0.578 M
Explanation:
We have equilibrium data for the chemical reaction in the gas phase:
SO2(g)+NO2(g)⇌NO(g) +SO3(g)
The equilibrium constant (Keq) for this reaction is 10.8.
Data for the components involved in this equilibrium are:
[SO3] = 1.7 M
[NO] = Unknown
[NO2] = 1.3 M
[SO2] = 0.07 M
We can express the Equilibrium constant as the multiplication of the concentrations of products divided by the multiplication of the concentration of reagents. After that, we can isolate [NO] concentration and find its value.
![Keq = \frac{[NO][SO3]}{[SO2][NO2]}\\Keq *[SO2][NO2] = [NO][SO3]](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5BNO%5D%5BSO3%5D%7D%7B%5BSO2%5D%5BNO2%5D%7D%5C%5CKeq%20%2A%5BSO2%5D%5BNO2%5D%20%3D%20%5BNO%5D%5BSO3%5D)
![[NO] = Keq \frac{[SO2][NO2]}{[SO3]}](https://tex.z-dn.net/?f=%5BNO%5D%20%3D%20Keq%20%5Cfrac%7B%5BSO2%5D%5BNO2%5D%7D%7B%5BSO3%5D%7D)
Replacing the values given in the problem
![[NO] = (10.8) \frac{[0.07M][1.3M]}{[1.7M]} = 0.578 M](https://tex.z-dn.net/?f=%5BNO%5D%20%3D%20%2810.8%29%20%5Cfrac%7B%5B0.07M%5D%5B1.3M%5D%7D%7B%5B1.7M%5D%7D%20%20%3D%200.578%20M)
Finally, the equlibrium concentration is [NO] = 0.578 M