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Over [174]
3 years ago
9

Which of the following is the FIRST step in solving the SI conversion problems?

Chemistry
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

A

Explanation:

Nina [5.8K]3 years ago
6 0

Answer:

It is A!

Explanation:

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Plzz help me out guys ......10 points rewarded.....!!!!!
GaryK [48]

number 5 is 1 : 1

number1 is also 1:1 ibelieve but it could be 2:1 just like number 5 but im postive its 1:1 for nummer 1 and number 5

4 0
3 years ago
You are able to see yourself in the mirror because of the wave property of
Anton [14]

Answer: c) reflection

Explanation:

8 0
3 years ago
Read 2 more answers
As the number of protons increases but the distance between the protons and electron REMAINS THE SAME...
Aloiza [94]

Answer:

The correct option is;

The electronegativity increases

Explanation:

The electronegativity is the measure of an atom's ability to attract a shared electron pair. The electronegativity of an atom is dependent on the atom's atomic number and the separation distance between the electrons in the valence shell and the positively charged nucleus such that an increase in the atomic number results in an increase in electronegativity and an increase in the distance between the valence electrons and the nucleus, leads to a decrease in electronegativity.

8 0
3 years ago
The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
musickatia [10]

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

3 0
3 years ago
For the chemical reaction
polet [3.4K]

Answer:

806.3g

Explanation:

Given parameters:

 Number of moles of silver nitrate  = 4.85mol

Unknown:

Mass of silver chromate = ?

Solution:

         2AgNO₃ + Na₂CrO₄  →  Ag₂CrO₄ + 2NaNO₃

To solve this problem, we work from the known to the unknown;

  • The known specie here is  AgNO₃ ;

   From the balanced chemical equation;

          2 moles of AgNO₃  will produce 1 mole of Ag₂CrO₄

          4.85 moles of AgNO₃  will produce \frac{4.85}{2}   = 2.43moles of Ag₂CrO₄

  • Mass of silver chromate produced;

        mass = number of moles x molar mass

   Molar mass of  Ag₂CrO₄

    Atomic mass of Ag = 107.9g/mol

                                 Cr  = 52g/mol

                                  O  = 16g/mol

  Input the parameters and solve;

     Molar mass  = 2(107.9) + 52 + 4(16) = 331.8g/mol

  So,

        Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g

     

8 0
3 years ago
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