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2 years ago

9

Which of the following is the FIRST step in solving the SI conversion problems?

2 answers:

AVprozaik [17]2 years ago

7 0

Answer:

A

Explanation:

Nina [5.8K]2 years ago

6 0

Answer:

It is A!

Explanation:

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Which statement correctly describes an atom of the element helium? A. An atom of helium has a full outer energy level and is the

Citrus2011 [14]

The correct description for an atom of helium would be option C. An atom of helium has its valence electrons in its first energy level, it wouldn't and can't satisfy the Octet rule as it only has 2 electrons, but with 2, it has a full shell, as the first energy level can hold only 2 electrons.

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2 years ago

Suppose 0.035 moles of HCl is dissolved in enough water to produce 750 mL of solution. What is the pH

zhuklara [117]

Answer:

pH = 1.33

Explanation:

Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.

Now we calculate the molar concentration (molarity) of H⁺:

Molarity = moles / volume

(750 mL ⇒ 750 / 1000 = 0.750 L)

Molarity = 0.035 moles / 0.750 L

Molarity = 0.0467 M

Then we calculate the pH of the solution:

pH = -log [H⁺]

pH = -log (0.0467 M)

pH = 1.33

5 0

2 years ago

How to balance Mg3n2+H20>>Mg(oh)2+Nh3?

alexandr1967 [171]

Mg₃N₂ + 6H₂O = 3Mg(OH)₂ + 2NH₃

4 0

3 years ago

3. Give one example of an element and one

zhenek [66]

Answer:

Element: H (hydrogen)

Compound: H2O (water)

Explanation: An element is made up of a singular atom while a compound is made up of 2 or more

7 0

3 years ago

Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many

Flauer [41]

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = $1.2kg/m^3=1.2g/L$ $(1kg/m^3=1g/L)$

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

8 0

3 years ago