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const2013 [10]
3 years ago
6

Which statement best defines work?

Physics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

c

Explanation:

I would think it would be c because that is what I would chose

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A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in
hammer [34]

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/m^{2}

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

I=\frac{P}{4\pi r^{2} }

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4\pi x^{2}

Second one is done with:

\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}

Solving for Intensity 2, the result mentioned.

The third is simply computed with

dB=10*log\frac{I}{10^{-12} }

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

8 0
3 years ago
One similarity between work and power is that in order to calculate both you must know
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D.) In order to calculate both of them, we must know the "FORCE" on the system.
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3 years ago
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Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x di
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Answer in photo below

6 0
2 years ago
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Ship A is located 4.1 km north and 2.3 km east of ship B. Ship A has a velocity of 22 km/h toward the south and Ship B has a vel
castortr0y [4]

Answer:

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

Explanation:

Given data:

A position is 4km north and 2.5 km east to B

Ship A velocity = 22 km/hr

ship B velocity = 40 km/hr

A velocity wrt to velocity of B

\vec{V_{AB}} =\vec{V_A} - \vec{V_B}

\vec{V_A} = 22 km/hr

\vec{V_B} = 40 cos38\hat{i} + 40sin 38 \hat{j}

                 = 31.52\hat{i} + 24.62 \hat{j}

putting respective value to get velocity of  A with respect to B

\vec{V_{AB}} = -22 \hat {j} - (31.52\hat{i} + 24.62 \hat{j})

\vec{V_{AB}} = -31.52\hat{i} - 46.62\hat{j}

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

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4 years ago
The speed of the object
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Speed of an object is kinetic energy
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