Ask question

Ask question

All categories

3 years ago

15

Spring 1 and Spring 2 are the same type of spring. Both springs were pushed or compressed into different positions and clamped i

nto place
L
Which spring has less potential energy?

1 answer:

frozen [14]3 years ago

8 0

Answer:

spring 1 has less potential energy

Explanation:

since spring 2 is clampped down further it will have a greater effect but since sping 1 is barely clamped down it wont show as much energy

You might be interested in

PLEASE HELP QUICKLY!!! <br> what happens to the motion of objects when they hit each other?

Monica [59]

Answer:

When two objects in motion hit each other they experience forces that are equal in magnitude and opposite in direction. This force causes one of the objects to speed up or gain momentum and other to slow down or lose momentum.

7 0

3 years ago

Help quick<br> ................

sattari [20]

The answer is B because there is a total of 10N to the right and 5 to the left, 10-5=5

4 0

3 years ago

What is the pressure at the bottom<br> of a 2.50 m deep pool of water?

Grace [21]

Answer:

Pressure = Density x Gravity acceleration x Height

Density of water = 1000 Kgm^-3

Gravity acceleration = 9.8 ms^-2

So it is 4.50.

Hope this helps and please mark me brainliest!

8 0

3 years ago

When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele

algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be $2.238\times 10^{-19}j$

Explanation:

In first case wavelength of electromagnetic radiation $\lambda =480nm=480\times 10^{-9}m$

Plank's constant $h=6.6\times 10^{-34}J-s$

Maximum kinetic energy = 0.54 eV

Energy is given by $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J$

We know that energy is given

$E=K_{MAX}+\Phi$ , here $\Phi$ is work function

So $4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi$

$\Phi =3.585\times 10^{-19}J$

Now wavelength of second radiation = 340 nm

So energy $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J$

So $K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j$

6 0

4 years ago

A busy waitress slides a plate of apple pie along a counter to a hungry customer sitting near the

Ostrovityanka [42]

Answer:

a. 0.5307 sec

b. 0.4458 m

c. = $v_x=0.84\ m/s\ ,\ v_y=5.2\ m/s$

Explanation:

Horizontal Motion

It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.

The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance $y_o$ , taking a time t to complete the travel. The formulas who relate the different magnitudes are

$v_x=v_o$

The horizontal velocity $v_x$ is the same regardless of the elapsed time

$v_y=gt$

$x=v_ot$

$\displaystyle y=y_o-\frac{gt^2}{2}$

The plate of apple pie left the counter at a speed

$v_o=0.84\ m/s$

The counter is $y_o=1.38\ m$ high.

a.

Knowing that

$y_o=1.38\ m$

We use this formula to compute t

$\displaystyle y=y_o-\frac{gt^2}{2}$

At the moment when the plate hits the floor y=0

$\displaystyle 0=y_o-\frac{gt^2}{2}$

$\displaystyle y_o=\frac{gt^2}{2}$

Solving for t

$\displaystyle t=\sqrt{\frac{2y_o}{g}}$

$\displaystyle t=\sqrt{\frac{2(1.38)}{9.8}}$

$t=0.5307\ sec$

b.

$x=(0.84)(0.5307)$

$x=0.4458\ m$

c.

$v_x=0.84\ m/s$

$v_y=(9.8)(0.5307)$

$v_y=5.2\ m/s$

3 0

4 years ago