Answer:
7.481W
Explanation:
power= work done÷time
power= force × uniform velocity
a= ∆v/t
29.0ms=
=(0.72-0)÷29×10^-3
a=24.83m/s^2
Newton's second law
f=ma
=(0.84×24.83)
=20.86N
w=FD
v^2=u^2+2as
0.5184=0+49.66s
s=0.0104m
20.86×0.0104
=0.216944J
0.216944÷t
P=7.481W
Answer:
(a) v = 1.71 m/s
(b) μ = 0.005
Explanation:
(a)
Using the law of conservation of the momentum:
where,
m₁ = mass of person = 61.1 kg
m₂ = mass of sled = 16.1 kg
u₁ = initial speed of the person = 2.16 m/s
u₂ = initial speed of the sled = 0 m/s
v₁ = v₂ = v = final speeds of both the person and the sled = ?
Therefore,
<u>v = 1.71 m/s</u>
<u></u>
(b)
The kinetic energy lost by the sled must be equal to the frictional energy:
K.E = fd
where,
μ = coefficient of kinetic friction = ?
d = distance covered = 30 m
g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>μ = 0.005</u>
Answer:
Required heat Q = 11,978 KJ
Explanation:
Given:
Mass = 5.3 kg
Latent heat of vaporization of water = 2,260 KJ / KG
Find:
Required heat Q
Computation:
Required heat Q = Mass x Latent heat of vaporization of water
Required heat Q = 5.3 x 2260
Required heat Q = 11,978 KJ
Required heat Q = 12,000 KJ (Approx.)
234-12=23 is the answer of this question