Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force
= frictional force 
so we can say that;
m×a = 
where;
the coefficient of static friction
is:



= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Answer:
Because the soundwave bounces back when it hits the wall. Only a fraction of the soundwave gets transferred through the wall.
Answer:
1)50000J
2) At the start of the trip
3) At the end of the trip
4) The higher the height above the ground, the higher the potential energy
5) As speed increases, Kinetic Energy increase
Answer:

Explanation:
Potential across the electrochemical cell, V = 2 V
Current, I = 1 A
Time, t = 1000 s
Let n electrons move from the anode to the cathode. We know that electric current is calculated as :

Also, q = ne




So,
electrons move from the anode to the cathode in 1000 seconds.
Answer:
yu counter the arguement by either walking out or confronting whats the problem then fixing that problem