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swat32
3 years ago
5

4 green marbles, 5 red marbles, and 2 yellow marbles are placed into a bag. One marble is chosen and replaced into the bag. A se

cond marble is chosen. What is the probability a red marble and then a yellow marble are chosen? Write answer in simplest fraction form,
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

The probability is 10/121

Step-by-step explanation:

In this question, we are tasked with calculating probability.

The probability to be calculated is that we have an ordered selection of picking a red marble after which we pick a yellow marble.

Firstly let us know the total number of marbles we have. That will be 4 + 5 + 2 = 11 marbles

Probability of picking a red marble will be 5/11 while the probability of picking a yellow marble will be 2/11

Now, the probability of picking a red marble before a yellow marble will be mathematically equal to; P(r) * P(y) = 5/11 * 2/11 = 10/121

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Answer:

m=\frac{8}{5}

Step-by-step explanation:

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Sanji scored 125 points in the first round of a video game and 263 points in the second round. His total score after the third r
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Answer:

  • At 1pm, the number of bacteria in the dish is 1,000,000
  • At 12pm, the number of bacteria in the dish is 500,000

Step-by-step explanation:

Given the information on the table

\left|\begin{array}{c|c}$Hour&$Number of Bacteria (in millions)\\---&--------------\\12 p.m.&\\1 p.m.&\\12 p.m.&\\2 p.m.&\\3 p.m.&\\4 p.m.&\\5 p.m.&32\\6 p.m.&64\end{array}\right|

We are to follow the pattern to determine how many million bacteria were in the dish at  1 p.m. and 12 p.m.

Now:

32=2^5\\64=2^6

It therefore means that the bacteria population doubles every hour. Following this pattern and reducing the exponents by 1 backwards, we have:

\left|\begin{array}{c|c}$Hour&$Number of Bacteria (in millions)\\---&--------------\\12 p.m.&2^{-1}=0.5\\1 p.m.&2^0=1\\12 p.m.&2^1=2\\2 p.m.&2^2=4\\3 p.m.&2^3=8\\4 p.m.&2^4=16\\5 p.m.&2^5=32\\6 p.m.&2^6=64\end{array}\right|

Therefore:

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3 0
3 years ago
A rectangular yard measuring 24 ft by 44 ft is bordered (and surrounded) by a fence. Inside, a walk that is 2 ft wide goes all t
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1 - First we can determine the area of the yard alone by doing:

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2 - Then, we can calculate the area of the walk by first subtracting two from the original values given ( 22 and 44 ), and then subtract the area of the yard with the value given in the equation we setup and solved below:

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3 - Stated in step 2, subtract 840 from the yard's area ( 968 feet squared ) to determine the space that is left over, that'll represent the 'walk' in this case:

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3 years ago
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