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swat32
3 years ago
5

4 green marbles, 5 red marbles, and 2 yellow marbles are placed into a bag. One marble is chosen and replaced into the bag. A se

cond marble is chosen. What is the probability a red marble and then a yellow marble are chosen? Write answer in simplest fraction form,
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

The probability is 10/121

Step-by-step explanation:

In this question, we are tasked with calculating probability.

The probability to be calculated is that we have an ordered selection of picking a red marble after which we pick a yellow marble.

Firstly let us know the total number of marbles we have. That will be 4 + 5 + 2 = 11 marbles

Probability of picking a red marble will be 5/11 while the probability of picking a yellow marble will be 2/11

Now, the probability of picking a red marble before a yellow marble will be mathematically equal to; P(r) * P(y) = 5/11 * 2/11 = 10/121

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Perimeter = 58.5 centimeters

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===============================================

Explanations:

To get the perimeter, you add up the three exterior (aka outer) sides. So you add up everything but the length measuring 13 cm, as this segment is not on the outside of the triangle. Imagine this is a parking lot and you want to put fencing around the outer sides. You won't build any fencing to run through the middle of the lot (assuming you don't want to subdivide)

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