Technically yes you are i think
Answer:
Kinetic energy is 1425.11 J.
Explanation:
Given:
Mass of the wrench is, ![m=655\ g=0.655\ kg](https://tex.z-dn.net/?f=m%3D655%5C%20g%3D0.655%5C%20kg)
Height of fall is, ![h=227\ m](https://tex.z-dn.net/?f=h%3D227%5C%20m)
Force of resistance is, ![F=0.141\ N](https://tex.z-dn.net/?f=F%3D0.141%5C%20N)
Now, the total energy at the top is equal to the potential energy of the wrench at the top since the kinetic energy at the top is 0.
Now, potential energy at the top is given as:
![U=mgh\\U=0.655\times 9.8\times 227\\U=1457.113\ J](https://tex.z-dn.net/?f=U%3Dmgh%5C%5CU%3D0.655%5Ctimes%209.8%5Ctimes%20227%5C%5CU%3D1457.113%5C%20J)
Now, the potential energy at the top is converted to kinetic energy at the bottom and some energy is wasted in overcoming the resistance force by air.
Potential Energy = Kinetic energy + Energy to overcome resistance.
⇒ Kinetic energy = Potential Energy - Energy to overcome resistance.
Energy to overcome resistance force is the work done by the wrench against the resistance force and is given as:
![W_{res}=Fh=0.141\times 227=32.007\ J](https://tex.z-dn.net/?f=W_%7Bres%7D%3DFh%3D0.141%5Ctimes%20227%3D32.007%5C%20J)
Therefore, Kinetic energy at the bottom is given as:
![K=U-W_{res}\\\\K=1457.113\ J - 32.007\ J\\\\K=1425.106\approx1425.11\ J](https://tex.z-dn.net/?f=K%3DU-W_%7Bres%7D%5C%5C%5C%5CK%3D1457.113%5C%20J%20-%2032.007%5C%20J%5C%5C%5C%5CK%3D1425.106%5Capprox1425.11%5C%20J)
Hence, the kinetic energy of the wrench be when it hits the water is 1425.11 J.
400m in 32sec: (400/32)>12.5meters per second>
(12.5)(60)(60)(1/1000)=45km per hour
Constant speed would mean that the two forces are equivalent
Answer:1.5×10 to the power of 17(unit-Hertz/H)
Explanation:V=F×Wavelength
F=V/Wavelength=3×10 to power/2×10 to power of -9=1.5×10 to power of 17
Answer:
The angular speed of the reel is 11.33 rad/s
Explanation:
Given
The fisherman takes t = 8.4 s to wind distance x = 2.9 m into a circle radius of r = 3 cm = 0.03 m
Than the tangencial speed equals the change in the distance to the time
v =
= ![\frac{2.9 m}{8.4 s} = 0.34 \frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B2.9%20m%7D%7B8.4%20s%7D%20%3D%200.34%20%5Cfrac%7Bm%7D%7Bs%7D)
Knowing the tangencial velocity is proportional to the radius r and the angular velocity
v = r*w
w = ![\frac{0.34 m/s}{0.03 m} = 11.33 \frac{rad}{s}](https://tex.z-dn.net/?f=%5Cfrac%7B0.34%20m%2Fs%7D%7B0.03%20m%7D%20%3D%2011.33%20%5Cfrac%7Brad%7D%7Bs%7D)