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storchak [24]
3 years ago
6

Help with all of them plsss

Physics
1 answer:
MakcuM [25]3 years ago
8 0
I):final velocity=initial velocity+acceleration due to gravity*time of travel

Therefore,
v=0+9.8*3.1
=30.38 m/s

If by floor you meant water bed then i think there isn't enough info in the question.
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Please help me!!!
natima [27]
<span>It is only possible if the fences has same voltage but different type of electric voltages(i.e. one, Ac voltage & another, Dc voltage). 

As having the same magnitude they varies in their properties. among them Ac has sinosuidal variation of voltage. that's why, Ac has large amplitude then the mean voltage(rms). 

+ Dc has constant magnitude. e.g. at home we know the recomended ac voltage is 220v(rms) but it raises upto 311


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7 0
3 years ago
Read 2 more answers
which relationship best represents the relationship between the magnitude of the centripetal acceleration and the speed of an ob
pashok25 [27]

the object's speed and centripetal acceleration in a circle with a constant radius is the exponential curve going up.

acceleration is the rate of change in both speed and direction of velocity over time. When something moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is constantly shifting, motion on a circle accelerates even when the speed is constant. Both effects add to the acceleration for all other types of motion.

It is a vector quantity because acceleration has both a magnitude and a direction. Another vector quantity is velocity. The velocity vector change over a given period of time, divided by that period of time, is the definition of acceleration. The upper limit of the ratio of velocity change provides instantaneous acceleration (at a specific time and place).

Learn more about  acceleration here:

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5 0
1 year ago
Why do people eat vegetables? Not just to stay healthy!!! But why else do we eat and need vegetables?
SVETLANKA909090 [29]

Answer:

Other reasons people eat vegetables are to get strong and get muscles, abs and I guess that people eat them because they taste good.

Explanation:

3 0
3 years ago
You are out running and the first mile takes you 10 minutes. The second mile takes you 20 minutes. This is an example of
cupoosta [38]

If Equal distance is traveled in equal interval of time then it is known as uniform motion in which velocity of object will remain same.

Then if distance covered will be same and the time taken to cover same distance is decreasing then it shows that speed is increasing with time due to which it took less time to cover same distance. This is also known as positive acceleration.

Now if the distance covered will be same and time taken to cover same distance is increasing then it shows that speed is decreasing with time due to which it took more time to cover the same distance. This is also known as negative acceleration.

Now in the above case it is given that the first mile takes you 10 minutes. The second mile takes you 20 minutes. So the time taken is increasing while we cover same distance so this is an example of <u>Negative Acceleration</u>

5 0
3 years ago
An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal.
Hitman42 [59]

Answer:

(a) max. height = 3.641 m

(b) flight time = 1.723 s

(c) horizontal range = 31.235 m

(d) impact velocity = 20 m/s

Above values have been given to third decimal.  Adjust significant figures to suit accuracy required.

Explanation:

This problem requires the use of kinematics equations

v1^2-v0^2=2aS .............(1)

v1.t + at^2/2 = S ............(2)

where

v0=initial velocity

v1=final velocity

a=acceleration

S=distance travelled

SI units and degrees will be used throughout

Let

theta = angle of elevation = 25 degrees above horizontal

v=initial velocity at 25 degrees elevation in m/s

a = g = -9.81 = acceleration due to gravity (downwards)

(a) Maximum height

Consider vertical direction,

v0 = v sin(theta) = 8.452 m/s

To find maximum height, we find the distance travelled when vertical velocity = 0, i.e. v1=0,

solve for S in equation (1)

v1^2 - v0^2 = 2aS

S = (v1^2-v0^2)/2g = (0-8.452^2)/(2*(-9.81)) = 3.641 m/s

(b) total flight time

We solve for the time t when the vertical height of the object is AGAIN = 0.

Using equation (2) for vertical direction,

v0*t + at^2/2 = S    substitute values

8.452*t + (-9.81)t^2 = 3.641

Solve for t in the above quadratic equation to get t=0, or t=1.723 s.

So time for the flight = 1.723 s

(c) Horiontal range

We know the horizontal velocity is constant (neglect air resistance) at

vh = v*cos(theta) = 25*cos(25) = 18.126 m/s

Time of flight = 1.723 s

Horizontal range = 18.126 m/s * 1.723 s = 31.235 m

(d) Magnitude of object on hitting ground, Vfinal

By symmetry of the trajectory, Vfinal = v = 20, or

Vfinal = sqrt(v0^2+vh^2) = sqrt(8.452^2+18.126^2) = 20 m/s

7 0
3 years ago
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