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Tasya [4]
3 years ago
7

What is the average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8

.0 s
Physics
1 answer:
Alex3 years ago
3 0

Answer:

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \frac{m}{s}.

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

velocity=\frac{displacement}{time}

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.

In this case, the displacement is 192 m and the time period is 8 s. Replacing:

velocity=\frac{192 m}{8 s}

Solving:

velocity= 24 \frac{m}{s}

<em><u>The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 </u></em>\frac{m}{s}<em><u>.</u></em>

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A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i
NARA [144]

Answer:

The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball.

Explanation:

In inelastic collision, the total momentum is always conserved after collision but the kinetic energy is reduced.

Momentum is Mass X velocity.

5 kg ball is in motion, while 10 kg ball is stationary; that is zero velocity.

The momentum of 10 kg ball before collision is zero while the momentum of 5 kg ball before collision is more than zero. Therefore, the magnitude of change in momentum will not be equal.

Next possible options are in kinetic Energy

Initial Kinetic energy = \frac{1}{2}mu^2

Final kinetic energy =\frac{1}{2}mv^2

Change in kinetic energy = Final Kinetic Energy - Initial Kinetic Energy

Change in kinetic energy of 5kg ball = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2

Since the 5-kg ball has initial velocity (u), the magnitude of the change in velocity will be reduced.

Change in kinetic energy of 10kg ball:

the ball is initially at rest, therefore the initial velocity (u) will be zero (0)

Δ K.E = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2 = \frac{1}{2}m(v-0)^2 = \frac{1}{2}mv^2

From the solution above, the magnitude of the change in velocity experienced by 10 kg ball is higher than 5 kg ball.

Hence, The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball

4 0
3 years ago
A crane exerts a net force of 900 N upward on a 750-kilogram car as the crane starts to lift the
Darya [45]

The acceleration of the car is 1.2 m/s^2 upward

Explanation:

We can solve the question by using Newton's Second Law of motion, which states that:

F=ma

where

F is the net force exerted on an object

m is the mass of the object

a is its acceleration

In this problem, we know that:

F = 900 N is the net force exerted on the car

m = 750 kg is the mass of the car

Solving the equation for a, we find the acceleration of the car:

a=\frac{F}{m}=\frac{900}{750}=1.2 m/s^2

and it is in the same direction as the force (upward).

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What factor affects sensation?
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One-half second after starting from rest, a freely falling object will have a speed of about:_________
snow_tiger [21]

One-half second after starting from rest, a freely falling object will have a speed of about 5 m/s.

<h3>What do you mean by falling object?</h3>

Falling things include goods, tools, garbage, and rubbish that are blown, dropped, or displaced from heights.

Physical science research frequently involves the study of gravity. Of course, what makes things fall is the force of gravity. A force of attraction between two objects is constant. This pulling force is similar to the pull of gravity.

given free fall from rest i.e.

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Answer:

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2. Phosphorylation reactions and proton pumping

Explanation:

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