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3 years ago

Which of these best describes Earth’s core?

Chemistry

2 answers:

navik [9.2K]3 years ago

6 0

the answer is a because the earth is made of different layers hens the core being a rock

Monica [59]3 years ago

5 0

Hello!

Your answer is A.. Earth's core is the most dense layer and it consists of the outer core and the inner core.

Hope this helps :))

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Compare the movement and arrangement of the molecules in solid nitrogen to those in nitrogen gas.

GuDViN [60]

solid nitrogen to those in nitrogen gas

4 0

2 years ago

Read 2 more answers

Complete the following reaction. 14/7 N + 1/0 n —> blank/blank C+1/1 H

Nataly_w [17]

Answer:

14/6

Explanation:

U 2 can help me by marking as brainliest........

8 0

1 year ago

Read 2 more answers

If the mass is 6.5g, and the volume is 25mL.. what is the density? PLEASE ANSWER ASAP

julia-pushkina [17]

Answer:

p = 260 kilogram/cubic meter

Explanation:

ρ = $\frac{m}{V} \\$

= $\frac{6.5 g}{25mL}$

= 0.26 gram/milliliter

= 260 kilogram/cubic meter

7 0

2 years ago

Find the mass of 4.5 moles of H3PO4

Contact [7]

Hey there!

H₃PO₄

Find molar mass.

H: 3 x 1.008 = 3.024

P: 1 x 30.97 = 30.97

O: 4 x 16 = 64

---------------------------------

97.994 grams

The mass of 1 mole of H₃PO₄ is 97.994 grams.

We have 4.5 moles.

97.994 x 4.5 = 440

The mass of 4.5 moles of H₃PO₄ is 440 grams.

Hope this helps!

6 0

2 years ago

If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did

user100 [1]

Answer:

4.5 L water we have in litres (L).

Explanation:

$Q=m\times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0 cal/(g℃))

m is the mass of water

Plugging in the values

$\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$$

So,

Volume of water = mass/density

$\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$$

=4.5 L (Answer)

6 0

3 years ago