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sergij07 [2.7K]
3 years ago
15

Which of these best describes Earth’s core?

Chemistry
2 answers:
navik [9.2K]3 years ago
6 0

the answer is a because the earth is made of different layers hens the core being a rock

Monica [59]3 years ago
5 0
Hello!

Your answer is A.. Earth's core is the most dense layer and it consists of the outer core and the inner core.

Hope this helps :))
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Is Fe2+ + 2e- = Fe an oxidation or reduction
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Answer:

oxidation

Explanation:

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Air pollution that forms from the interaction between chemicals in the air and sunlight
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This process is called Photochemical smog

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What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = 5\times 196.96 g

4.99 moles of gold contain = 984.8 g

Mass of {3.01\times 10^{24}} atoms of gold = 984.5 g

<u>Part II :</u>

Density of Gold = 19.32 g/cm^{3}

Volume of the cuboid = length\times breadth\times height

Volume of the gold bar =6.00\times 4.25\times 2.00

Volume of the gold bar = 51cm^{3}

Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

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3 years ago
What happens in the process of polymerization?
ruslelena [56]

Answer:

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Explanation:

5 0
3 years ago
Can somebody help me with this also plz
just olya [345]

ANSWER:

4 a) Specific elements have more than one oxidation state, demonstrating variable valency.

For example, the following transition metals demonstrate varied valence states: Fe^{2+}, Fe^{3+}, Cr^{2+}, Cr^{3+}, etc.

Normal metals such as Pb^{2+} and Pb^{4+} also show variable valencies. Certain non-metals are also found to show more than one valence state Pb^{3+} and Pb^{5+}.

4 b) Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons.

For example, Carbon-14 is a naturally occurring radioactive isotope of carbon, having six protons and eight neutrons in the nucleus. However, C-14 does not last forever and there will come a time when it loses its extra neutrons and becomes Carbon-12.

5 a) 2Fe + 3Cl_2 → 2FeCl_3    

5 b) 3Pb + 8HNO_3 → 3Pb (NO_3)_2 + 4H_2O + 2NO_2

5 c) Zn + H_2SO_4 → ZnSO_4 + H_2   (already balanced so don't need to change)

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EXPLANATION (IF NEEDED):

1. Write out how many atoms of each element is on the left (reactant side) and right (product side) of the arrow.

2. Start multiplying each side accordingly to try to get atoms of the elements on both sides equal.

EXAMPLE OF BALANCING:

8 0
2 years ago
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