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umka2103 [35]
3 years ago
14

How much heat energy is needed to heat 300g of water from 10 degrees Celsius to 50 degrees Celsius

Chemistry
1 answer:
elixir [45]3 years ago
8 0

Answer:

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

Explanation:

<u>Step 1: </u>Data given

mass of water = 300 grams

initial temperature = 10°C

final temperature = 50°C

Temperature rise = 50 °C - 10 °C = 40 °C

Specific heat capacity of water = 4.184 J/g °C

<u>Step 2:</u> Calculate the heat

Q = m*c*ΔT

Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)

Q = 50208 Joule = 50.2 kJ

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

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Answer:

The answer to your question is  V2 = 1244 L

Explanation:

Data

Temperature 1 = 11°C

Volume = 1.03 x 10³ L

Temperature 2 = 70°C

Volume 2 = ?

To solve this problem use the Charles' law

        V1/ T1 = V2 / T2

-Solve for V2

        V2 = V1T2 / T1

Process

1.- Convert temperature to °K

Temperature 1 = 11°C + 273 = 284°K

Temperature 2 = 70°C + 273 = 343°K

2.- Substitution

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3.- Simplification

        V2 = 353290 / 284

4.- Result

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5 0
3 years ago
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Answer:

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Explanation:

Hello,

In this case, considering the given percentages, we compute the mole ratios as shown below:

n_C=\frac{0.545}{12}=0.0454\\n_H=\frac{0.1373}{1}=0.1373\\n_N=\frac{0.3177}{14}=0.0227

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C_2H_6N

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