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umka2103 [35]
2 years ago
14

How much heat energy is needed to heat 300g of water from 10 degrees Celsius to 50 degrees Celsius

Chemistry
1 answer:
elixir [45]2 years ago
8 0

Answer:

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

Explanation:

<u>Step 1: </u>Data given

mass of water = 300 grams

initial temperature = 10°C

final temperature = 50°C

Temperature rise = 50 °C - 10 °C = 40 °C

Specific heat capacity of water = 4.184 J/g °C

<u>Step 2:</u> Calculate the heat

Q = m*c*ΔT

Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)

Q = 50208 Joule = 50.2 kJ

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

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Advantages and disadvantages of titration?
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Answer:

What are the advantages of titration?

Titrimetric analysis commonly referred to as volumetric analysis offers distinct advantages over cumbersome gravimetric methods:

Speed of analysis.

Instantaneous completion of reactions.

Greater accuracy due to minimization of material loss involved in decanting, filtration, precipitation or similar operations.

Explanation:

Disadvantages

It is a destructive method often using up relatively large quantities of the substance being analysed.

It requires reactions to occur in a liquid phase, often the chemistry of interest will make this inappropriate.

It can produce significant amounts of chemical waste which has to be disposed of.

It has limited accuracy.

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2 years ago
What happens to the velocity when you apply a constant force to an<br> object? *
Degger [83]

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8 0
3 years ago
What material could be used for a cup to keep coffee hot
nata0808 [166]

Answer:

Your answer could be: ceramic or stainless steel.

Explanation:

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4 0
3 years ago
if 4.12 L of 0.85-M H3PO4 solution is be diluted to a volume of 10.00 L,what is the concentration resulting solution
Alja [10]

Answer:

The concentration resulting solution = 0.350 M

Explanation:

In case of dilution , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = initial concentration ,

V₁ = initial volume ,

M₂ = final concentration , i.e. , concentration after dilution ,

V₂ = final volume .

from , the question ,

M₁ = 0.85 M

V₁ = 4.12 L

M₂ = ?

V₂ = 10.0 L

Using the above formula , the molarity of the final solution after dilution , can be calculated as ,

M₁V₁ = M₂V₂

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M₂ = 0.85 M * 4.12 L  / 10.0 L

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5 0
3 years ago
Which element is located in group 2 period 2 on the periodic Table?
AnnZ [28]

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Explanation:

you are welcome

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2 years ago
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