Answer:
i believe that the answer is D: wavelength
Answer:
The magnitude of Electric Field is 
Explanation:
Given:
- Radius of the solid sphere=R
- Total charge of the sphere=Q
Let consider a Gaussian surface at a distance of r such that 0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.
The charge inside this Gaussian surface volume we have , 
Now using Gauss Law we have
Answer:
<h2>Tt will take 4.04 seconds</h2>
Explanation:
In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken
Given that
final velocity= 3.4m/s
initia velocity u= 0m/s
deceleration= 0.84 m/s^2
time t= ?
applying
v=u+at
Substituting our given data into the expression above we have
3.4=0+0.84t
3.4=0.84t
divide both sides by 0.84 we have
3.4/0.84= t
t= 4.04 seconds
λ = c : f
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.86 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.86
E = 1.896 x 10⁻³³ J
λ = 3 x 10⁸ : 1.011 x 10⁸
λ = 2.97 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.97
E = 1.97 x 10⁻³³ J
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.96 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.96
E = 1.96 x 10⁻³³ J
Answer:
An initial velocity that is faster than a final velocity.
Explanation:
