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Gnesinka [82]
3 years ago
12

Pnrjrjjrjrjrrmdmmdmdmdmdmdjd

Physics
2 answers:
Degger [83]3 years ago
4 0

Answer:

why would you waste points

Explanation:

Vinil7 [7]3 years ago
3 0

Answer:

dhgkajsgdajsbsvhjhsjs

Explanation:

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Select the correct answer.
Sergeeva-Olga [200]

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All of the above.

Explanation:

All of these steps are useful towards getting a job.

8 0
3 years ago
a force is something that causes change in motion . what provides the force that made the cart speed up brainly/
Maurinko [17]

Answer:

the unbalanced force

Explanation:

An unbalance forces are defined as the forces which causes a change in the speed or velocity of a moving object. A force causes a change in the motion of a body and an unbalanced force causes the body to change its velocity and speed or a change in its direction.

An unbalanced force will start movement in a static object or it can cause to speed up the moving object or it can cause to stop the moving object.

Thus an unbalanced force causes the cart to speed up.

4 0
3 years ago
When the velocity of the car is constant the force of friction is?
miv72 [106K]
..... equal to the force from the engine pushing the car forward.

That's why the car is not accelerating.  The horizontal forces on it
are balanced.
6 0
3 years ago
What's the difference between a wavelength and an an amplitude?
valkas [14]
Wavelength - the distance from one wave crest or trough to another wave crest or trough. Amplitude - the distance from the median point or "middle" of the wave straight up to a crest (a maximum) or straight down to a trough (or minimum), which is the peak amplitude; or the distance from a trough straight up to a crest, or a crest straight down to a trough, called peak-to-peak amplitude.
3 0
4 years ago
Read 2 more answers
A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
KATRIN_1 [288]

Complete Question

Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?

Answer:

The value  is  T_R  = 11.8 \  days  

Explanation:

From the question we are told that

   The semi - major axis of the rocky debris  a_R = 45.0\  AU

   The semi - major axis of  Planet D is  a_D  = 60 \  AU

    The orbital  period of planet D is  T_D = 18.164 \  days

Generally from Kepler third law

          T \  \ \alpha \ \ a^{\frac{3}{2} }

Here T is the  orbital period  while a is the semi major axis

So  

        \frac{T_D}{T_R}  =  \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}

=>     T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }  

=>     T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }

=>      T_R  = 11.8 \  days  

   

7 0
3 years ago
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