Let's find the discriminant of <span>x^2+9x+14=0. Here, a=1, b=9 and c=14.
The discriminant is b^2-4ac. Substituting the above numeric values,
9^2-4(1)(14) = 81-56 = 25
The sqrt of 25 is 5. Thus, your polynomial has two unequal, real roots.
Off the point example: If the discriminant were zero, your poly would have two real, equal roots.</span>
Answer:
None
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x - 2
x = 3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function]: f(3) = 4(3) - 2
- Multiply: f(3) = 12 - 2
- Subtract: f(3) = 10
A+7=0
A+7-7=0-7
A=-7
B+3=7
B+3-3=7-3
B=4
Answer:
Its A
Step-by-step explanation:
