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Anarel [89]
4 years ago
10

PLZ ANSWER NOW FOR BRAINLEIST ANSWER AND 30 points!!! Show all work

Mathematics
2 answers:
Darina [25.2K]4 years ago
7 0
A simple method is to square all the answers 

6^2 = 36~~~( \sqrt{40} )^2 = 40 ~~5^2 = 25 ~~~~ (\sqrt{23} )^2 = 23

now arrange them
horsena [70]4 years ago
7 0
Sqrt 40 is between two perfect squares, sqrt 36 and sqrt 49.
Sqrt 40 is greater than 6 and less than 7.

Sqrt 23 is between the perfect squares 16 and 25.
Sqrt 23 is greater than ; and less than 5.

Sqrt23, 5, 6, sqrt40,
You might be interested in
Determine if the sequence below is arithmetic or geometric and determine the common difference ratio in simplest form. 11,7,3
HACTEHA [7]
The sequence is Arithmetic

d = -4

4 0
3 years ago
Sali throws an ordinary fair 6 sided dice once.
xenn [34]

a) 1/6

b) 1/36

c)

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

Step-by-step explanation:

a)

The probability of a certain event A to occur is given by

p(A)=\frac{a}{n}

where

a is the number of successfull outcomes, in which event A occurs

n is the total number of possible outcomes

In this problem, the event is

"getting a 6 when throwing a dice once"

We know that the possible outcomes of a dice are six: 1, 2, 3, 4, 5, 6, so we he have

n=6

The successfull outcome in this case is only if we get a 6, so only 1 outcome, therefore

a=1

So, the probability of this event is

p(6)=\frac{1}{6}

b)

In this case instead, we are throwing the dice twice.

The two throws of the dice are independent events (one does not depend on the other): the probability that two independent events A and B occur at the same time is given by the product of the individual probabilities,

p(AB)=p(A)\cdot p(B)

where

p(A) is the probability that event A occurs

p(B) is the probability that event B occurs

Here we have:

- Event A is "getting a 6 in the first throw of the dice". We already calculated this probability in part a), and it is

p(A)=\frac{1}{6}

- Event B is "getting a 6 in the second throw of the dice". Since the dice has not changed, the probability is still the same, so

p(B)=\frac{1}{6}

Therefore, the probability of getting a 6 on both throws is:

p(66)=p(6)\cdot p(6)=\frac{1}{6}\cdot \frac{1}{6}=\frac{1}{36}

c)

In this problem, we have:

- A dice that is thrown once

- A coin that is also thrown once

The dice has 6 possible outcomes, as we stated in part a):

1, 2, 3, 4, 5, 6

While the coin has two possible outcomes:

H = head

T = tail

So, in order to find all the outcomes of the two events combined, we have to combine all the outcomes of the dice with all the outcomes of the coin.

Doing so, using the following notation:

1H (getting 1 with the dice, and head with the coin)

The possible outcomes are:

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

So, we have a total of 12 possible outcomes.

4 0
3 years ago
What is |–14|<br>A. 1/14<br>B. -7<br>C. -14 <br>D. 7<br>E. 14​
expeople1 [14]

Answer:

14

Step-by-step explanation:

absolute value works where it doesnt matter if the number is positive or negative. the absolute value is the number positive. an absolute value can not be negative.

5 0
3 years ago
A manufacturer of precision measuring instruments claims that the standarddeviation in the use of the instruments is less than 0
alexdok [17]

Answer:

i) There is insufficient evidence to support the claim that the standard deviation of the instruments is less than 0.00002 millimeters.

ii) p_v= P(\chi^2_{7}

Step-by-step explanation:

s=0.00001 represent the sample standard deviation

\alpha =0.01 represent the significance level for the test

\sigma_o =0.00002 represent the value that we want to test

n=8 represent the sample size

A chi-square test can be used to test "if the standard deviation of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test".

Null and alternatve hypothesis

The system of hypothesis on this case would be given by:

Null Hypothesis: \sigma \geq 0.00002

Alternative Hypothesis: \sigma

The statistic to test this is given by:

T=(n-1)(\frac{s}{\sigma_0})^2   (1)

Part i) Calculate the statistic

If we replace into formula (1) we got this:

T=(8-1)(\frac{0.00001}{0.00002})^2 =1.75   (1)

The critical region for a for a lower one-tailed alternative is given by

T< \chi^2_{1-\alpha/2,N-1}

The degrees of freedom are given by

df=n-1=8-1=7

And if we use the Chi Square distribution with 7 degrees of freedom we see that \chi^2_{1-0.01/2,7}=1.239

And our critical region would be T< 1.239 so on this case we can conclude that we fail to reject the null hypothesis. So it's not enough evidence to conclude that the population standard deviation is less than 0.00002 mm.

Part ii) Calculate the p value

In order to calculate the p value we can do this:

p_v= P(\chi^2_{7}

If we compare this value with the significance level (0.01) we see that p_v>\alpha

This agrees with the conclusion since when the p values is greater than the significance level we FAIL to reject the null hypothesis, same conclusion as part i).

7 0
3 years ago
Find the product of -8 (-12)​
Aneli [31]
The answer is 96.

-8 ( -12 ) = 96

Negative times negative equals positive
7 0
3 years ago
Read 2 more answers
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