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Alexeev081 [22]
3 years ago
12

Wire A carries 4 A into a junction, wire B carries 5 A into the same junction, and another wire is connected to the junction. Wh

at is the current in this last wire?
Physics
1 answer:
nydimaria [60]3 years ago
7 0

Answer:9A

Explanation:

let the last wire be wire C

According to Kirchhoff's rule

the sum of all currents entering a junction must be equal to the sum of all currents leaving a junction

Ic=Ia+Ib

Ic= 4+5

Ic=9A

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An object is accelerating if it is moving____. circle all that apply. ​
tino4ka555 [31]

Answer:

With changing speed and/or in a circle

3 0
3 years ago
Light of wavelength 550 nm comes into a thin slit and produces a diffraction pattern on a board 8.0 m away. The first minimum da
FrozenT [24]

Answer:

Width of the slit will be equal to 1.47 mm

Explanation:

We have given wavelength of the light \lambda =550nm=550\times 10^{-9}m

Distance D = 8 m

Distance between first minimum dark fringe and the central maximum is 2 mm

So x=3\times 10^{-3}m

We have to find the width of the slit

For the first order wavelength is equal to \lambda =\frac{x}{D}\times a, here a width of slit

So a=\frac{\lambda D}{x}=\frac{550\times 10^{-9}\times 8}{3\times 10^{-3}}=1466.666\times 10^{-6}=1.47mm

So width of the slit will be equal to 1.47 mm

5 0
3 years ago
A thin, light wire 75.2 cm long having a circular cross section 0.560 mm in diameter has a 25.2 kg weight attached to it, causin
blsea [12.9K]

Answer:

The stress is calculated as 1.003\times 10^{9}\ Pa

Solution:

As per the question:

Length of the wire, l = 75.2 cm = 0.752 m

Diameter of the circular cross-section, d = 0.560 mm = 0.560\times 10^{- 3}\ m

Mass of the weight attached, m = 25.2 kg

Elongation in the wire, \Delta l = 1.10\ mm = 1.10\times 10^{- 3}\ m

Now,

The stress in the wire is given by:

Stress,\ \sigma = \frac{Force,\ F}{Area,\ A}          (1)

Now,

Force is due to the weight of the attached weight:

F = mg = 25.2\times 9.8 = 246.96\ N

Cross  sectional Area, A = \pi (\frac{d}{2})^{2} = \pi (\frac{0.560\times 10^{- 3}}{2})^{2} = 2.46\times 10^{- 7}\ m^{2}

Using these values in eqn (1):

\sigma = \frac{246.96}{2.46\times 10^{- 7}} = 1.003\times 10^{9}\ Pa  

8 0
2 years ago
. Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connecte
Umnica [9.8K]

Given :

Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.

To Find :

Will the heat produced in both the cases be equal.

Solution :

Heat released is given by :

H = i²Rt

Here, R is resistance and is given by :

R = \dfrac{\rho L}{A}

So,

H = i^2\times \dfrac{\rho L}{A} t\\\\H = \dfrac{i^2\rho Lt}{A}

Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.

So, heat produced by Reem's wire is more than Nain one.

Hence, this is the required solution.

7 0
2 years ago
Explain why ventilation is very important if there is risk of exposure to random gas in your home school
bonufazy [111]
Ventilation is very important because it helps remove the gas form people’s homes and schools and it redirects the random gas outside so it is less likely to hurt people
3 0
3 years ago
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