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qwelly [4]
3 years ago
6

Skylar goes to a pumpkin patch and pick out a pumpkin that has a mass of 6000 grams how many kilograms is the pumpkin

Physics
2 answers:
Alex3 years ago
6 0
1000g = 1kg
6000g =6000 × 1/1000
=6kg
myrzilka [38]3 years ago
3 0
The answer is 2
721.55422 kilograms
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At time t=0 a positively charged particle of mass m=3.57 g and charge q=9.12 µC is injected into the region of the uniform magne
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Answer:

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Explanation:

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F^{\to}= qE^{\to} +q (v^{\to} + B^{\to}) \\ \\  F^{\to} = (9.12 \times 10^{-6}) *278 (-\hat k) +9.12 *10^{-6} *2.1 *0.18 (\hat i * \hat k) \\ \\  F^{\to} = -2.535 *10^{-3} \hat k -3.447*10^{-6} \hat j

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∴

a ^{\to}= \dfrac{F^{\to}}{m}

a ^{\to}= \dfrac{-1}{3.57\times 10^{-3}}(2.535*10^{-3}\hat k + 3.447*10^{-6} \hat j)

a ^{\to}=-0.710 \hat k -9.656*10^{-4} \hat j

At time t(sec; the partiCle velocity becomes v(t) = 3.78 v_o

The velocity of the charge after the time t(sec) is expressed by using the formula:

v^{\to}= v_{o \ \hat i} + a^{\to }t \\ \\  \implies (2.1)\hat i -0.710 t \hat k -9.656 \times 10^{-4} t \hat j = 3.78 v_o \\ \\ \implies (2.1)^2 +(0.710\ t)^2+ (9.656 *10^{-4}t )^2 = (3.78 *2.1^2 \\ \\ \implies 4.41 +0.5041 t^2 +9.324*10^{-7} t^2 = 63.012 \\ \\ \implies 4.41 +0.5041 t^2 = 63.012\\  \\  0.5041t^2 = 63.012-4.41 \\ \\ t^2 = \dfrac{58.602}{0.5041} \\ \\ t^2 = 116.25 \\ \\ t = \sqrt{116.25} \\ \\  \mathbf{t = 10.78 \ s}

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