Answer:
Explanation:
The observed frequency of the double crossovers (DCOs) is 20/1000, or 0.02. If there is no interference then this will be the same as the expected, which is just the product of the single crossover frequencies, that is, SCO frequency (a-b) x SCO freq. (b-c) = 0.02.
(a) Any combination of map distances whose product (a-b) x (b-c) = 0.02 is possible. However, three are most likely:
a 20 mu b 10 mu c
a 10 mu b 20 mu c
a 14.14 mu b 14.14 mu c
(b) The distances would be exactly the same.
(c) The expected number of DCO progeny would be 17.
Answer:
B) A kidney malfunction that removes more water than normal
Explanation:
Just took the test :)
Also, the answer choice is worded differently for me. The alternative answer is "A kidney malfunction that removes more water than normal".
Answer
if B and b are the two alleles , B + b = 1 and B ^2 +2 Bb + b ^2
= 1. If 16% of mice are homozygous black , B ^ 2 =0 .16, meaning B = 0 .4 and b = 1 - 0.
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The correct answer is that mutant cells will exhibit diminished oxygen consumption; decreased glycolysis results in decreased Kreb's cycle and electron transport chain.
The PFK2 enzyme catalyzes the generation of F26BP, this binds with the allosteric site of PFK-1 and increases the affinity of PFK-1 with F6P and also decreases the affinity of allosteric inhibitors citrate and ATP to PFK-1. Thus, PFK-1 will combine with F6P at a greater rate.
This ultimately results in more glycolysis, thus, more ETC and more consumption of O2. If there is no PFK2, then there will be a reduction in glycolysis, TCA, ETC, and consumption of oxygen.
The PFK2 is an enzyme accountable for monitoring the rates of gluconeogenesis and glycolysis in the human body. In the absence of glycolysis, there will be a reduction in TCA, ETC, and consumption of O2.
Answer:
rashes is caused by heat while skin infection is caused by bacteria and infection