Luke Autbeloe drops an approximately 5.0 kg object (weight = 50.0 N) off the roof of his house into the swimming pool below. Upo
n encountering the pool, the object encounters a 50.0 N upward resistance force (assumed to be constant). Use this description to answer the following questions. (Down is usually considered a negative direction) a. Which one of the velocity-time graphs best describes the motion of the object? Why?
1 answer:
Answer:
Graph B represents correct graph for velocity time
Explanation:
Initially the object is dropped under the influence of constant force due to gravity
So here we can say its acceleration is constant due to gravity
hence here the velocity will increase downwards due to gravity and it is given as
now when it enters into the pool an upward force of same magnitude will act on it
so net force on it is
so here we will have no acceleration and it will move with constant speed after that
so here correct graph is
Graph B
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Explanation:
It is given that,
Input voltage,
Input current,
Output current,
Number of turns in the secondary side of transformer,
We need to find the number of turns in the primary side of the transformer. The current to the number of turns in the input and output is given by :
Substituting all the above values
So,
So, the number of turns in primary side of the transformer is 5885.
Answer:
Resistance in the flash tube,
Explanation:
It is given that,
Speed of the bullet, v = 500 m/s
Distance between one RC constant, d = 1 mm = 0.001 m
Capacitance,
The time constant of RC circuit is given by :
R is the resistance in the flash tube
..........(1)
Speed of the bullet is given by total distance divided by total time taken as :
Equation (1) becomes :
So, the resistance in the flash tube is . Hence, this is the required solution.
Answer:
Explanation:
Check attachment for solution.
Generally the movement of the knight is L, i.e (2,1), (1,2),(-1,2),(1,-2) etc.
So using Pythagoras theorem
x^2+y^2=1^2+2^2
x^2+y^2=5
Then, the knight will make one movement when the displacement is √5.
So let take a look at other positions
(1,0),(0,1),(-1,0), (0,-1).
Then, for us to have this kind of movement, the knight has to make 3 movements.
When the displacement is 1, then it will make 3 movement.
Let examine other positions
(2,2) or(-2,-2) or (2,-2) or (-2,2)
When the displacement is √8
Then, the movement of the knight is 4.
Let examine other points
(2,0) or (0,2) or (-2,0) or (0,-2)
When the displacement is 2.
The knight make 2 movement
