The potential difference comes out to be

Given:
σ = 8. 85 × 10-9 c/m2
we know,



given the potential difference between two equipotential surface=5v
E=∆v
∆d=∆v/E


Thus the potential difference is

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It would be 12hz because it
The voltage<span> difference between the two plates can be expressed in terms of the </span>work<span> done on a positive test charge q when it moves from the positive to the negative plate.</span><span>
E=V/d
where V is the voltage and d is the distance between the plates.
So,
E=6.0V/1mm= 6000 V/m. The electric field between the plates is 6000 V/m.</span>
Answer:
The pressure remains the same.
F = P * A the amount of force transmitted would double if only the input area is changed. Pressure is the same at all points in the system.