3 years ago

What is the ostrich’s average acceleration from 9.0 to 18s

Physics

1 answer:

algol [13]3 years ago

3 0

Answer:

Explanation:

10.00 5

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Lunna [17]

Answer:

h−200m

p−1060kg/m

g−9.8m/s

Patm:−1.013×10 N/m2

FORMULA:

P=P

+hpg

= 1.013×10+200×1060×9.8

= 21.789×10

N/m

Explanation:

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3 years ago

A 0.3-m-radius automobile tire rotates how many revolutions after starting from rest and accelerating at a constant 2.13 rad/s2

Aloiza [94]

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

$\theta = \omega_i \ + \frac{1}{2} \alpha t^2$

the initial angular velocity is zero,

$\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad$

Find how many revolutions that are in 573.2256 Rad

$N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions$

Therefore, the automobile tire rotates 91 revolutions

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4 years ago