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Vera_Pavlovna [14]
3 years ago
12

After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

<em></em>

I hope it helps!

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Potassium and fluorine are both halogens?​
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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
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Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

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2.- Substitution

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4.- Result

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