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lapo4ka [179]
3 years ago
13

A rock that has a mass if 180 grams dropped in a graduated cylinder that was originally filled to 52ml; it now reads 62ml. What

is the density of this object ​
Chemistry
1 answer:
Vlad [161]3 years ago
5 0

Answer:

<h2>18 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 62 - 52 = 10 mL

From the question we have

density =  \frac{180}{10}  \\

We have the final answer as

<h3>18 g/mL</h3>

Hope this helps you

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Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to
valina [46]

5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.

<u>Explanation</u>:

  • Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:

                        Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃

  • From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of  H₂SO₄.
  • Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and                                Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
  • To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is =  5.451 X 10³ kg.

 

5 0
3 years ago
If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th
mr_godi [17]

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

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Carbon monoxide = CO = in excess

Step 2: The balanced equation

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Step 3: Calculate moles of O2

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Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

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