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3 years ago

Explain why the roller coaster’s potential energy is greater at point 1 than at point 4.

Chemistry

1 answer:

vodomira [7]3 years ago

8 0

Answer:

The answer to your question is given below.

Explanation:

Potential energy is the energy stored in a body by virtue of its location. Mathematically, potential energy is expressed as:

Potential energy (P.E) = Mass(m) x Acceleration due to gravity (g) x Height (h)

P.E = mgh

Since the mass of the object is always constant and the acceleration due to gravity is also constant, it therefore means that the potential energy of an object is directly proportional to the height where the object is located.

This implies that as the height to which the object is located increases, the potential energy of the object also increases and as the height to which the object is located decreases, the potential energy of the object will also decrease.

In the diagram given above, point 1 is higher than point 4. This will cause the potential energy of the roller to be higher at point 1 than at point 4.

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Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react

Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of $BCl_3$ = 60 g

Mass of $H_2O$ = 37.5 g

Molar mass of $BCl_3$ = 117 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HCl$ = 36.5 g/mole

First we have to calculate the moles of $BCl_3$ and $H_2O$ .

$\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)$

From the balanced reaction we conclude that

As, 1 mole of $BCl_3$ react with 3 mole of $H_2O$

So, 0.513 moles of $BCl_3$ react with $3\times 0.513=1.539$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $BCl_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $HCl$ .

As, 1 mole of $BCl_3$ react to give 3 moles of $HCl$

So, 0.513 moles of $BCl_3$ react to give $3\times 0.513=1.539$ moles of $HCl$

Now we have to calculate the mass of $HCl$ .

$\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl$

$\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g$

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0

3 years ago

How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?

Anna [14]

Answer:

12 moles of F₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

Xmol of F₂ = (3 × 8)/2

Xmol of F₂ = 12 moles

Thus, 12 moles of F₂ is needed for the reaction.

8 0

3 years ago

Q2.Which is true about potassium?

Olenka [21]

$\bf \LARGE\rightarrow{Very \: reactive}$

5 0

3 years ago

Read 2 more answers

How much heat is required to produce 2 moles of C2H2?

Kruka [31]

Answer: To calculate the enthalpy of combustion of acetylene, C2H2 , all you have to do is ... More specifically, you need to subtract from the sum of enthalpies of ... chemical reaction has 2 moles of C2H2 reacting to produce 2 moles of ... since the heat of combustion is expressed as energy per mole

5 0

3 years ago

The temperature of a 500 ml sample of gas increases from 150 k to 300 k. what is the final volume of the sample of gas, if the p

seropon [69]

Upon a constant pressure (P), volume (V) of a gas will vary in direct proportion to changes in temperature (T). So V1/T1 = V2/T2
V2 = V1T2/T1 = (500)(300)/150
V2 = 150000/150 = 1000 mL

5 0

3 years ago