It's about dividing the like-terms. Obviously 20/4 is 5, but then each variable has to be divided. The exponents of the variables in division are subtracted, so with the x-value it would be 1 - 3, which is -2. Do this with the other variables, and you should get C
We know the amount of copper is 85%, that means the rest is tin in the Alloy, so the tin is 15% of the Alloy then.
now, say "x" lbs is the total amount of the Alloy, and we know that 1 and 13/32 which is tin, is the 15% of "x", what the dickens is "x"?
![\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ x&100\\\\ 1\frac{13}{32}&15 \end{array}\implies \cfrac{x}{1\frac{13}{32}}=\cfrac{100}{15}\implies \cfrac{x}{\frac{1\cdot 32+13}{32}}=\cfrac{20}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%0Aamount%26%5C%25%5C%5C%0A%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C%0Ax%26100%5C%5C%5C%5C%0A1%5Cfrac%7B13%7D%7B32%7D%2615%0A%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7Bx%7D%7B1%5Cfrac%7B13%7D%7B32%7D%7D%3D%5Ccfrac%7B100%7D%7B15%7D%5Cimplies%20%5Ccfrac%7Bx%7D%7B%5Cfrac%7B1%5Ccdot%2032%2B13%7D%7B32%7D%7D%3D%5Ccfrac%7B20%7D%7B3%7D)
Answer:
There are 4 integers between 27 and 53 that have a remainder of 4 divided by 6.
Step-by-step explanation:
At first we need to find which integers between 27 and 53 are divisible by 6, which are, respectively:
![A =\{30, 36, 42, 48\}](https://tex.z-dn.net/?f=A%20%3D%5C%7B30%2C%2036%2C%2042%2C%2048%5C%7D)
All integers that have a remainder of 4 divided by 6 are found by summing 4 to each element of A, that is:
![A' = \{34,40,46, 52\}](https://tex.z-dn.net/?f=A%27%20%3D%20%5C%7B34%2C40%2C46%2C%2052%5C%7D)
There are 4 integers between 27 and 53 that have a remainder of 4 divided by 6.
Answer:
The answer is y=-3/5x-6
Step-by-step explanation:
y-y=m(x-x1)
y-(-3)=-3/5(x-(-5))
y+3=-3/5x-3
-3 -3
y=-3/5x-6
AD > EC
the 25° angle is more inclined than the other