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scZoUnD [109]
3 years ago
10

A hydrate is ​typically a crystalline compound in which water molecules are chemically bound to another compound or an element.

​When CuSO​4​​⋅​ 5H​2​O is heated in a crucible, there is a loss of water. How should a student determine the amount of water lost?
a.Subtract the mass of the CuSO​4​ from the mass of CuSO​4​⋅ 5H​2​O
b.Subtract the mass of the CuSO​4​⋅ 5H​2​O from the mass of CuSO​4
c.Add the masses of CuSO​4​⋅ 5H​2​O and CuSO​4
d.Multiply the masses of CuSO​4​⋅ 5H​2​O and CuSO​
Chemistry
1 answer:
dedylja [7]3 years ago
7 0

Answer:

Subtract the mass of the CuSO4⋅ 5H2O from the mass of CuSO4 is the right one

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Please help thaank youu
krek1111 [17]
First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
Co=58.933
Cl=35.45
H=1.008
O=15.999

Now, let's find the mass of each compound.

CoCl_2=58.933+2(35.45)=129.833
H_2O=2(1.008)+15.999=18.015

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

6(18.015)=108.09
129.833+108.09=237.923

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

\dfrac{108.09}{237.923}

\approx0.45431

Turn that into a percentage and you get 45.431%.
Hope this helps! :)
6 0
3 years ago
BIOCHEMISTRY HELP! You and a lab partner are performing on several molecular analogs to determine Km. One is a substrate analog,
Alina [70]

Answer:

Michaelis constant is known as km which is the substrate concentration that encourages the compound to work at half maximum velocity represented by Vmax/2. Michaelis constant is inversely related to the substrate and the affinity of the enzyme.  

Induced fit model: The premise of the purported induced fit hypothesis, which expresses that the attachment or association of a substrate or some other atom to an enzyme causes an adjustment to the enzyme in order to fit or restrain its activity.  

In substrate, analog Km or Michaelis constant will be high as the substrate will stay because of analogs inhibit activity.

In the transitional state, analog Km will be in the middle of the substrate and product analogs. Progress state analogs are synthetic mixes with a structure catalyzed reaction that looks like the progressing condition of a substrate atom in a compound enzyme.  

In item simple thus Km is the least.  

0.0013 M = product ananlog,

0.025 M=Transition state, and

0.0045 M = Substrate analog

5 0
3 years ago
In the laboratory, a student dilutes 13.5 mL of a 11.6 M hydroiodic acid solution to a total volume of 100.0 mL. What is the con
igomit [66]

Answer: The concentration of the diluted solution is 1.566M.

Explanation:

The dilution equation is presented as this: M_{s} V_{s} =M_{d} V_{d}.

·M= molarity (labeled as M)

·V= volume (labeled as L)

·s= stock solution (what you started with)

·d= diluted solution (what you have after)

Now that we know what each part of the formula symbolizes, we can plug in our data.

11.6M*13.5mL=M_{d} *100mL

We cannot leave it like this because the volumes must be in Liters, not milliliters. To convert this, we divide the milliliters by 1000.

13.5mL/1000=0.0135L     100mL/1000=0.1L

Now that we have the conversions, let's plug them into the equation.

11.6M*0.0135L=M_{d} *0.1L

The only thing that we need to do now is actually solving the answer.

M_{d} =\frac{11.6M*0.0135L}{0.1L}       M_{d} =1.566M

From the work shown above, the answer is 1.566M.

I hope this helps!! Pls mark brainliest :)

7 0
2 years ago
..............................................
Vilka [71]
The period is the end of the sentence!!!
6 0
3 years ago
Butanol is composed of carbon, hydrogen, and oxygen. If 1.0 mol of butanol contains 6.0 x 1024 atoms of hydrogen, what is the su
yanalaym [24]

Answer:

Option B. 10

Explanation:

If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.

(number of atoms  / NA)

6.02 x 10²³ atoms ___ 1 mol

6×10²⁴ atoms will occupy (6×10²⁴ / NA) = 9.96 moles

H, has 10 moles in the butano formula.

4 0
3 years ago
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