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sdas [7]
3 years ago
8

Determine the maximum theoretical speed that may be achieved over a distance of 66 m by a car starting from rest, knowing that t

he coefficient of static friction is 0.80 between the tires and the pavement and that 60 percent of the weight of the car is distributed over its front wheels and 40 percent over its rear wheels.
Physics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

v=32.49 m/s

Explanation:

Given that

Distance ,d= 66 m

Initial speed of the car ,u = 0 m/s

Coefficient of friction ,μ = 0.8

Lets take the total mass of the car = m

The acceleration of the car is given as

a = μ g                               ( g= 10 m/s² )

Now by putting the values in the above equation we get

a= 0.8 x 10 m/s²

a= 8 m/s²

We know that ,final speed is given as

v²= u ²+ 2 a d

Now putting the value

v²=0² + 2 x 8 x 66

v²= 1056

v=32.49 m/s

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a motorcyclist starts from rest and accelerates at rate of 4 meters per second squared north. what is the final velocity of the
MArishka [77]

Answer:

80m<em>/</em><em>s</em>

Explanation:

Final velocity is given by

v=u+at

when a motorcyclist starts from rest, initial velocity (u) =0

therefore

v=0+4*20

v=80m/s

that's the answer

8 0
4 years ago
An object experiences an acceleration of -6.8m/s^2. As a result, it accelerates from 54m/s to a complete stop. how much distance
Kipish [7]

Answer:

210 m

Explanation:

Given:

a = -6.8 m/s²

v₀ = 54 m/s

v = 0 m/s

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx

Δx ≈ 210 m

6 0
3 years ago
The heart working with the blood vessels to pump blood is which body system?
LiRa [457]
I think it’s the cardiovascular system
6 0
3 years ago
As a science fair project, you want to launch an 950 g model rocket straight up and hit a horizontally moving target as it passe
Aleksandr-060686 [28]

Answer:

As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?

= 43.56m

Explanation:

acceleration =

(20 - (0.95 * 9.8) )/ (0.95)

= 10.68 / 0.95

= 11.24 m/s²

we use

s = ut + (1/2) at²

Given that

s= 40

u =0  

s = 0 * t + (1/2) (11.24)t²

t = √(66/1.24)

t = √5.87

t = 2.42sec

hence

Horizontal distance = 18 * 2.42

= 43.56m

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3 years ago
According to the law of conservation of matter, the number of ________ is not changed by a chemical reaction.
kondaur [170]
The answer should be atoms.
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3 years ago
Read 2 more answers
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