Answer:
80m<em>/</em><em>s</em>
Explanation:
Final velocity is given by
v=u+at
when a motorcyclist starts from rest, initial velocity (u) =0
therefore
v=0+4*20
v=80m/s
that's the answer
Answer:
210 m
Explanation:
Given:
a = -6.8 m/s²
v₀ = 54 m/s
v = 0 m/s
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx
Δx ≈ 210 m
I think it’s the cardiovascular system
Answer:
As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?
= 43.56m
Explanation:
acceleration =
(20 - (0.95 * 9.8) )/ (0.95)
= 10.68 / 0.95
= 11.24 m/s²
we use
s = ut + (1/2) at²
Given that
s= 40
u =0
s = 0 * t + (1/2) (11.24)t²
t = √(66/1.24)
t = √5.87
t = 2.42sec
hence
Horizontal distance = 18 * 2.42
= 43.56m