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lapo4ka [179]
3 years ago
11

When dc generators are operated in parallel to supply power for a single load, their controls include an equalizer circuit to as

sure that all generators share the load equally. The equalizer circuit operates by:___________
A) Decreasing the output of the high generator to equal the output of the low generator.
B) Increasing the output of the low generator to equal the output of the high generator.
C) Increasing the output of the low generator and decreasing the output of the high generator until they are equal
Physics
1 answer:
adell [148]3 years ago
7 0

Answer:

The equalizer circuit operates by:

<em><u>The answer is</u></em>  option C (Increasing the output of the low generator and decreasing the output of the high generator until they are equal)

Explanation:

A DC generator has four basic parts: a commutator, a single conductor or loop,  a magnetic field, and  brushes. A DC generator which is built utilizing the basic principle that emf (Electromotive force) is induced in a conductor  when it cuts magnetic lines of force is an electrical machine which converts mechanical energy into direct current electricity.

An equalizer circuit operates by maintaining an equal sharing of the load between all generators in a DC generator system.

Parallel operation of DC generators is required to meet the extra load demand. Some of the conditions that must be met for parallel operation Of DC Generator is: the terminal voltage must be the same, the change of voltage with the change of load must be the same character, and the polarities of the generator must be identical.

The output voltage of the high generator is decreased, and the output voltage of the low generator is increased, once the load is shared unequally.

 

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Rudiy27

Answer:

Approximately 7.66\; \rm m.

Explanation:

<h3>Solve this question with a speed-time plot</h3>

The skateboarder started with an initial speed of u = 1.75\; \rm m \cdot s^{-1} and came to a stop when her speed became v = 0\; \rm m \cdot s^{-1}. How much time would that take if her acceleration is a = -0.20\; \rm m \cdot s^{-1}?

\begin{aligned} t &= \frac{v - u}{a} \\ &= \frac{0\; \rm m \cdot s^{-1} - 1.75\; \rm m \cdot s^{-1}}{-0.20\; \rm m \cdot s^{-2}} \approx 8.75\; \rm s\end{aligned}.

Refer to the speed-time graph in the diagram attached. This diagram shows the velocity-time plot of this skateboarder between the time she reached the incline and the time when she came to a stop. This plot, along with the vertical speed axis and the horizontal time axis, form a triangle. The area of this triangle should be equal to the distance that the skateboarder travelled while she was moving up this incline until she came to a stop. For this particular question, that area is approximately equal to:

\displaystyle \frac{1}{2} \times 1.75\; \rm m \cdot s^{-1} \times 8.75\; \rm s \approx 7.66\; \rm m.

In other words, the skateboarder travelled 15.3\; \rm m up the slope until she came to a stop.

<h3>Solve this question with an SUVAT equation</h3>

A more general equation for this kind of motion is:

\displaystyle x = \frac{1}{2}\, (u + v) \, t = \frac{1}{2}\, (u + v)\cdot \frac{v - u}{a}= \frac{v^2 - u^2}{2\, a},

where:

  • u and v are the initial and final velocity of the object,
  • a is the constant acceleration that changed the velocity of this object from u to v, and
  • x is the distance that this object travelled while its velocity changed from u to v.

For the skateboarder in this question:

\begin{aligned}x &= \frac{v^2 - u^2}{2\, a}\\ &= \frac{\left(0\; \rm m \cdot s^{-1}\right)^2 - \left(1.75\; \rm m \cdot s^{-1}\right)^2}{2\times \left(-0.20\; \rm m \cdot s^{-2}\right)}\approx 7.66\; \rm m \end{aligned}.

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