Answer:
The work done on the wagon is, W = 4531 J
Explanation:
Given data,
The displacement of the circus wagon, S = 23 m
The elephant pulled with a force, Fₐ = 250 N
The angle of direction of force with the horizontal, Ф = 38°
Therefore, the force in the horizontal direction is,
F = Fₐ Cos Ф
The work done on the wagon is
W = F · S
= Fₐ Cos Ф · S
= Fₐ · S · Cos Ф
= 250 · 23 · Cos 38°
= 4531 J
Hence, the work done on the wagon is, W = 4531 J
Answer:the mass Of The object,and there area Of The bottom surface
Explanation:
There mass Of The object, and the area Of The bottom surface
Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope

Now, we know frequency is given by :

Therefore, the frequency of the second harmonic is 3 s⁻¹.
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⊄L∅∪⊥ G∀NG
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