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anyanavicka [17]
3 years ago
7

The releasing of an object from certain height to ground due to gravity is called____ A, Free falling B, Projectile C, curved li

near D,para pola​
Physics
1 answer:
MArishka [77]3 years ago
7 0

Answer:

projectile

Explanation:

when an object is released from certain height to ground due to gravity is called projectile

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g A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n
malfutka [58]

Question:

A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n = 7 in nm?

Answer:

<em></em>\lambda_n = 5.71\ nm<em></em>

<em></em>

Explanation:

Given

L = 20nm --- the width

n = 7

Required

Determine the wavelength (\lambda)

This is calculated as:

\lambda_n = \frac{2L}{n}

Substitute values for L and n

\lambda_n = \frac{2*20nm}{7}

\lambda_n = \frac{40nm}{7}

\lambda_n = \frac{40}{7}nm

\lambda_n = 5.71428571\ nm

<em></em>\lambda_n = 5.71\ nm<em> --- approximated to 3 significant figures</em>

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3 years ago
What is the common abbreviation for millimeters, centimeters,meters
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meter m

centimeter cm

millimeter mm

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2 years ago
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No. If I count the number of tiny blue eggs in a Robin's nest, that's a quantitative observation.
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3.25 kcal is the same amount of energy as
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3 years ago
Read 2 more answers
A person walks 45 m East and then walks 39 m at an angle 40◦ North of East. What is the magnitude of the total displacement? Ans
vredina [299]

Answer:

r = 78.95 m

Explanation:

given,

Person Walk in east, r₁ = 45 m

Then he walk, r₂= 39 m in the direction of 40◦ North of East.

writing the total displacement in x- direction

 r₁ₓ  = 45 m

 r₂ₓ = 39 cos 40°

  r₂ₓ = 29.87 m

total displacement in x-direction

rₓ = r₁ₓ + r₂ₓ

rₓ = 45 + 29.87

rₓ = 74.87 m

displacement in y-direction

r_{1y} = 0 m

r_{2y} = 39 sin 40°

r_{2y} = 25.07 m

total displacement in y- direction

  r_y = 25.07 m

using Pythagoras theorem for the magnitude calculation

 r = \sqrt{r_x^2 + r_y^2}

 r = \sqrt{74.87^2 +25.07^2}

        r = 78.95 m

The magnitude of total displacement is equal to 78.95 m.

8 0
3 years ago
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