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3 years ago

Write down the second term in the sequence given by: T(n) = n2 - 5

Mathematics

1 answer:

enot [183]3 years ago

8 0

There are two terms n2 and -5. n2 is the first term and -5 is the second term

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Admission to the fair costs $8.75. Each ride costs $0.50 to ride. You can spend at most $16. Write and solve an inequality to re

sergij07 [2.7K]

8.75 + 0.50 =9.25 dollars spend but she has 16 dollars so 16 - 9.25 = 6.75 dollars left

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2 years ago

The engine of a car has a displacement of 305 cubic inches. what is the displacement in cubic feet? round your answer to 2 decim

ipn [44]

solution
1 inch = 2.54 centimeters
Therefore, to convert to cubic measurements
(1 in)³ = (2.54 cm)³
Thus;
1 in³ = 16.387 cm³
Hence 305 cubic inches will be equivalent to
305 × 16.387
= 4998.035 cm³

5 0

3 years ago

Read 2 more answers

So I need someone to asnwer this ASAp since my he is due in 20 minutes. Please help!

dem82 [27]

A)6 ^^^^^^^^^^^^because

5 0

3 years ago

Part - A

Oduvanchick [21]

Answer:

rule add 15 subtract 10

Step-by-step explanation:

rule add 15 subtract 10

5 0

2 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago