3 years ago

If a cart of a roller coaster has a mass of 250kg and is at a height of 14 meters. What is the cart's potential energy?

Physics

1 answer:

ahrayia [7]3 years ago

5 0

Answer:

3430000 J

Explanation:

The formula for potential energy is PE=mgh.

M being the mass, g being the force of gravity, and h being the height.

First thing you want to do is convert 250 kg to g (grams).

From there you get 25000g and you have to multiply that by 14m and 9.8m/s^2 (the force of gravity is constant, at least on earth).

You might be interested in

What is the name of the process that involves a strong attractive force that keeps atoms together

Novay_Z [31]

Answer:

chemical bond

Explanation:

7 0

3 years ago

Read 2 more answers

Sinkholes can form when

kherson [118]

Land surfaces change, erosion happens, the ground collapses, etc.

7 0

3 years ago

Read 2 more answers

the train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?

Anvisha [2.4K]

18meters per 20 seconds so

5 0

3 years ago

Read 2 more answers

A playground merry-go-round of radius 2.00 m has a moment of inertia I = 275 kg · m2 and is rotating about a frictionless vertic

ryzh [129]

Answer:

0.2932 rad/s

Explanation:

r = Radius = 2 m

$I_i$ = Initial angular momentum = $275\ kgm^2$

$\omega_i$ = Initial angular velocity = 14 rev/min

$I_f$ = Final angular momentum

$\omega_f$ = Final angular velocity

Here the angular momentum of the system is conserved

$I_i\omega_i=I_f\omega_f\\\Rightarrow 275\times 14\times \dfrac{2\pi}{60}=(275+275(2)^2)\omega_f\\\Rightarrow \omega_f=\dfrac{275\times 14\times \dfrac{2\pi}{60}}{275+275(2)^2}\\\Rightarrow \omega_f=0.2932\ rad/s$

The final angular velocity is 0.2932 rad/s

7 0

3 years ago

Find the mass of a person who weighs 608 N

Anvisha [2.4K]

Answer:

$weight = mass \times accelaration \: due \: to \: gravity \\ 608 = x \times 10 \\ x = 608 \div 10 = 60.8 \\ mass = 60.8 \\ thank \: you$

7 0

3 years ago

Read 2 more answers