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Lostsunrise [7]
1 year ago
9

How did the angular acceleration change with the new moment of inertia? was your prediction correct?

Physics
1 answer:
elena55 [62]1 year ago
6 0

In Newtonian physics, the acceleration of a body is inversely proportional to mass. In Newtonian rotational physics, angular acceleration is inversely proportional to the moment of inertia of a frame.

The moment of Inertia is frequently given the image I. it's miles the rotational analog of mass. The moment of inertia of an object is a measure of its resistance to angular acceleration. because of its rotational inertia, you want torque to change the angular pace of an object. If there may be no net torque acting on an object, its angular speed will no longer change.

In linear momentum, the momentum p is the same as the mass m instances of the velocity v; whereas for angular momentum, the angular momentum L is the same as the instant of inertia I times the angular pace ω.

Learn more about angular acceleration here:-brainly.com/question/21278452

#SPJ4

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saul85 [17]
Observe as many moose as he can in as many locations as possible.
6 0
3 years ago
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A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h
Butoxors [25]

Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is m_1=1.6\times 10^4 kg

speed of bus towards North v_1=15.2 km/h\approx 4.22\ m/s

mass of bus travelling in South direction is m_2=1.578\times 10^4 kg

speed of bus v_2=12.2 km/h\approx 3.38\ m/s

mass of each Passenger in south moving bus m_0=64.8 kg

Momentum of North moving bus

P_1=m_1\times v_1

P_1=1.6\times 10^4\times 4.22

P_1=6.768\times 10^4 kg-m/s

Momentum with south moving bus

P_2=m_2\times v_2+n\cdot m_0\times v_2

P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38

For total momentum to be towards south

P_2-P_1 should be greater than 0

thus for least value of n

P_2=P_1

(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4

1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4

n=\frac{4243.6686}{64.8}=65.48\approx 66    

5 0
3 years ago
Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie
Bond [772]

Answer:

Explanation:

For parallel inductors ,

\frac{1}{L_R} = \frac{1}{L_1} +\frac{1}{L_2}

\frac{1}{L_R} =\frac{1}{25} +\frac{1}{50}

L_R=16.67 mH.

For series combination

Total inductance

= 16.67 + 20

= 36.67 mH .

reactance of total inductance at 300 kHz

= ωL_{total} where ω is angular frequency

= 2πfL_{total}

= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³

= 69.1 x 10³ ohm

Total rms current = Vrms / reactance

= 60 / 69.1 x 10³ A

= .87 x 10⁻³ A

= .87 mA

7 0
3 years ago
What happens to the kinetic energy of a body when: a) the mass of the body is doubled at constant velocity? b) the velocity of t
blagie [28]
Using the formula KE=1/2mv^2

a: The kinetic energy doubles.
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Hopefully it’s clear how the formula can show you this.
3 0
3 years ago
Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject
Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

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specific impulse = 300 sec

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earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}

where

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t = 12,105.96 sec

6 0
3 years ago
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