It makes no difference whether there are two bulbs or 1000 bulbs. If they are all in series then when one bulb burns out, or one little piece of wire between two bulbs comes loose, ALL of them go dark. In that situation it's a challenge to find where the break in the circuit is because all of the bulbs are dark.
This would be called the battery. Hope this helps.
Answer:
Wave Variables
In the chapter on motion in two dimensions, we defined the following variables to describe harmonic motion:
Amplitude—maximum displacement from the equilibrium position of an object oscillating around such equilibrium position
Frequency—number of events per unit of time
Period—time it takes to complete one oscillation
For waves, these variables have the same basic meaning. However, it is helpful to word the definitions in a more specific way that applies directly to waves:
].
Explanation:
The tension in the rope B is determined as 10.9 N.
<h3>
Vertical angle of cable B</h3>
tanθ = (6 - 4)/(5 - 0)
tan θ = (2)/(5)
tan θ = 0.4
θ = arc tan(0.4) = 21.8 ⁰
<h3>Angle between B and C</h3>
θ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰
Apply cosine rule to determine the tension in rope B;
A² = B² + C² - 2BC(cos A)
B = C
A² = B² + B² - (2B²)(cos A)
A² = 2B² - 2B²(cos 43.6)
A² = 0.55B²
B² = A²/0.55
B² = 65.3/0.55
B² = 118.73
B = √(118.73)
B = 10.9 N
Thus, the tension in the rope B is determined as 10.9 N.
Learn more about tension here: brainly.com/question/24994188
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Answer:
117.83° F
Explanation:
Using Newton's Law of Cooling which can be expressed as:
The differential equation can be computed as:
where;
At the initial condition, T(0)= 350
replacing 
= 280 into (1)
Hence, the differential equation becomes:
when;
time (t) = 1 hour
T(1) = 250
Since;
k = -0.4418
Therefore;
T(t) = 70 + 280e^{(-0.4418)}t
After 4 hours, the temperature is:
T(t) = 70 + 280e^{(-0.4418)}4
T(4) = 117.83° F
