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3 years ago

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Suppose a horizontal wind blows with a speed of 12.6 m/s outside a large pane of plate glass with dimensions 3.00 m x 1.80 m. As

sume the density of the air to be 1.30 kg/m3. The air inside the building is at atmospheric pressure. What If? If a second skyscraper is built nearby, the airspeed can be especially high where wind passes through the narrow separation between the buildings. (c) Find the pressure with a wind speed twice as high.

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

Explanation:

Given to find the pressure

v = 12.6 m/s , A = 3.0m * 1.8 m = 54 m^2

p air = 1.3 kg/m^3

F = 1/2 * p *v^2 *A

F = 1/2 *1.3 kg/m^3 * (12.6 m/s)^2 * 54m^2

F = 5572.476 N

The stress and the pressure can find across the area

α = F /A

α = 5572.476 N / 54 m^2

α = 103.194 Pa

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