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astraxan [27]
3 years ago
11

Suppose a horizontal wind blows with a speed of 12.6 m/s outside a large pane of plate glass with dimensions 3.00 m x 1.80 m. As

sume the density of the air to be 1.30 kg/m3. The air inside the building is at atmospheric pressure. What If? If a second skyscraper is built nearby, the airspeed can be especially high where wind passes through the narrow separation between the buildings. (c) Find the pressure with a wind speed twice as high.
Physics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

Explanation:

Given to find the pressure

v = 12.6 m/s , A = 3.0m * 1.8 m = 54 m^2

p air = 1.3 kg/m^3

F = 1/2 * p *v^2 *A

F = 1/2 *1.3 kg/m^3 * (12.6 m/s)^2 * 54m^2

F = 5572.476 N

The stress and the pressure can find across the area

α = F /A

α = 5572.476 N / 54 m^2

α = 103.194 Pa

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Which forces are shown on a free body diagram?
notsponge [240]

Answer:

What is a Free Body Diagram?

The free body diagram helps you understand and solve static and dynamic problem involving forces. It is a diagram including all forces acting on a given object without the other object in the system. You need to first understand all the forces acting on the object and then represent these force by arrows in the direction of the force to be drawn.

Explanation:

5 0
3 years ago
Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the
Gala2k [10]

Answer:

40 V

Explanation:

 I will assume that  the resistors are

           100 and 3900 and 1000 OHMS    <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R      so the total current will be   200 v / 5000 ohms = .04 amps

                   this is the current through all of the resistors

      so for the   1000 ohm resistor     V = IR     .04 (1000) = 40 V

7 0
2 years ago
How do you find the oscillation period in seconds for different pendulum lengths?
GalinKa [24]

To find:

The equation to find the period of oscillation.

Explanation:

The period of oscillation of a pendulum is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity.

Thus the period of a pendulum is given by the equation,

T=2\pi\sqrt{\frac{L}{g}}

Where L is the length of the pendulum and g is the acceleration due to gravity.

On substituting the values of the length of the pendulum and the acceleration due to gravity at the point where the period of the pendulum is being measured, the above equation yields the value of the period of the pendulum.

Final answer:

The period of oscillation of a pendulum can be calculated using the equation,

T=2\pi\sqrt{\frac{L}{g}}

3 0
1 year ago
In the equation for the gravitational force between two objects, what does G represent? the gravitational constant the gravitati
kumpel [21]
G is the gravitational constant, which is approximately 6.6x10^-11 Nm/s^2. It has the same value regardless of the masses of both objects or the distance between them.
3 0
3 years ago
Read 2 more answers
A wave of infrared light has a speed of 6m/s and a wave length of 12 m. What is the frequency of this wave?
erastovalidia [21]
Frequency = speed / wavelength

(6 m/s) / (12 m) = 0.5 Hz.

That's not infrared light.
Infrared light waves move about 50 million times faster than that, and they're only about 0.00000007 as long as that.
6 0
4 years ago
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