Answer:
The maximum load the bar can withstand = 35.43 KN
Explanation:
Ultimate tensile strength of the given aluminium bar 
= 540 M pa
Cross section area of the bar = 
= 65.61 
We know that the ultimate strength of the bar is calculated from
= 540 × 65.61
= 35.43 KN
Therefore the maximum load the bar can withstand = 35.43 KN
Answer:
N_A=1.5*10^-8 kmol/s.m^2
Explanation:
<u>KNOWN: </u>
Molar concentration of helium at the inner and outer surfaces of a plastic membrane. Diffusion coefficient and membrane thickness.
<u>FIND:</u>
Molar diffusion flux.
<u>ASSUMPTIONS:</u>
(1) Steady-state conditions, (2) One-dimensional diffusion in a plane wall, (3) Stationary medium, (4) Uniform C = C_A + C_B.
<u>ANALYSIS:</u> The molar flux may be obtained from
N_A=D_AB/L(C_A,1-C_A,2)
=10^-9 m^2/s/0.001 m(0.02-0.005)kmol/m^3
N_A=1.5*10^-8 kmol/s.m^2
<u>COMMENTS:</u> The mass flux is:
n_A,x=M_a*N_A,x
n_A,x=6*10^-8 kg/s m^2
Answer:
divide then add XD my guy this is easy
Explanation:
I think the correct answer is B
