Question
Determine the average water exit velocity
Answer:
53.05 m/s
Explanation:
Given information
Volume flow rate, 
Diameter d= 8cm= 0.08 m
Assumptions
- The flow is jet flow hence momentum-flux correction factor is unity
- Gravitational force is not considered
- The flow is steady, frictionless and incompressible
- Water is discharged to the atmosphere hence pressure is ignored
We know that Q=AV and making v the subject then
where V is the exit velocity and A is area
Area,
where d is the diameter
By substitution

To convert v to m/s from m/s, we simply divide it by 60 hence

Answer:
resistance = 2.52 ohms
Explanation:
from the formula
V =IR
Voltage = (current)(resistance)
Resistance =
R=
R= 2.52 ohms
Answer: hope this helps u
Explanation:
Material,Flexibility,Comfort,Workplace Hazards
Answer:
for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns
Explanation:
Vp/Vs= Np/Ns
Vp: Primary voltage
Vs: Secondary Voltage
Np: number of turns on primary side
Ns: number of turns on secondary side
for output 5.6V
140/5.6= 220/Ns
Ns= 8.8 or 9 Turns
for output 12.0V
140/12= 220/Ns
Ns= 18.9 or 19 turns
for output 480V
140/480= 220/Ns
Ns= 754.3 or 755 turns