Answer:
symbolic machine code.
Explanation:
The instructions in the language are closely linked to the machine's architecture.
If your accelerator gets stuck down, do the following:
Shift to neutral.
Apply the brakes.
Keep your eyes on the road and look for a way out.
Warn other drivers by blinking and flashing your hazard lights.
Try to drive the car safely off the road.
Turn off the ignition when you no longer need to change direction.
Answer:
The answer is "Both Technician A and Technician B".
Explanation:
The cylinder Testing is intended to assess locomotive inconsistency in CNS rodents, for example, whenever the animal moves within a transparent plastic tube, its preliminary activity is registered as it rises against the stadium wall.
In the given question both technicians are correct because both are reliable ways to check cylinders and the influence of the belief if every pathway has many more advantages than each other.
Answer:
First compute the characteristic length and the Biot number to see if the lumped analysis is applicable
Lc = V/A = (pie*D3/6) / (pie * D2)= 1.2/6 = 0.0012/6= 0.0002m
Bi = hLc/K = (110W/m2.oC)(0.0002)(moC/35W)= 110*0.0002/35 = 0.0006 less than 0.1
Since the Biot number is less than 0.1, we can use the lumped parameter analysis.
In such an analysis, the time to reach a certain temperature is given by
t = -1/bIn(T-Tinfinite/T - Tinfinite)
From the data in the problem we can compute the parameter, b, and then compute the time for the ratio (T – Tinfinite/(Ti – Tinfinite) to reach the desired value.
b = hA/pCpV = h/pCpLc = 110/8500*0.0002 *320*s
b = 110/544s = 0.2022/s
The problem statement is interpreted to read that the measured temperature difference T – Tinfinite has eliminated 98.5% of the transient error in the initial temperature reading Ti – Tinfinite so the value of value of (T – Tinfinite)/(Ti – Tinfinite) to be used in this equation is 0.015
t = -1/bIn(T-Tinfinite/T - Tinfinite)
t = -s/0.1654 (In0.015)
t = (-s*-4.1997)/0.2022
t = 20.77s
It will take the thermocouple 20.77s to reach 98.5% of the initial temperature