2 years ago

Hello, I have a question, I would be glad if you can help.

Engineering

1 answer:

Anastasy [175]2 years ago

3 0

Answer:

infinite

Explanation:

The tangent of the angle the arm makes with the vertical will be the ratio of the centripetal acceleration to the acceleration due to gravity on the center of mass of the arm. The angle can only be 90° (fully-open arms) if that ratio is infinite.

The speed must be infinite for the arms to be fully open.

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3 years ago

Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^

Nat2105 [25]

Answer:

The answer is " $\bold{ 259.2 \times 10^{11} }$ ".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

$M= -DAt \frac{\Delta C}{ \Delta x} \\\\$

$D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \ sec \\\\$

calculating the value of $\Delta C:$

$\Delta C =C_A -C_B$

$= 2.4 - 0.6 \\\\ = 1.8 \ \ \frac{kg}{m^3}$

calculating the value of $\Delta X:$

$\Delta x = x_{A} -x_{B}$

$= 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m$

$M = -(1.0 \times 10^{8} \times 0.20 \times 3600 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\$

$= -(1.0 \times 10^{8} \times 720 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8} \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8} \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\$