Question

What volume does .0685 mol of gas occupy at STP? 1mole =22.4

Answer 1

Answer : The volume of gas at STP is, 1.53 liter

Solution : Given,

Moles of a gas = 0.0685 mole

As we know that at STP,

1 mole of gas contains 22.4 liter volume of gas

As, 1 mole of gas contains 22.4 liter volume of gas

So, 0.0685 mole of gas contains $0.0685\times 22.4=1.53L$ volume of gas

Therefore, the volume of gas at STP is, 1.53 liter

Answer 2

V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm