All categories

3 years ago

What volume does .0685 mol of gas occupy at STP? 1mole =22.4

Chemistry

2 answers:

SashulF [63]3 years ago

6 0

Answer : The volume of gas at STP is, 1.53 liter

Solution : Given,

Moles of a gas = 0.0685 mole

As we know that at STP,

1 mole of gas contains 22.4 liter volume of gas

As, 1 mole of gas contains 22.4 liter volume of gas

So, 0.0685 mole of gas contains $0.0685\times 22.4=1.53L$ volume of gas

Therefore, the volume of gas at STP is, 1.53 liter

GuDViN [60]3 years ago

4 0

V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm

You might be interested in

Fault-block mountains are formed when a shift takes place along a fault line and

worty [1.4K]

One side drops into fault

7 0

3 years ago

By which mechanism would a steroid molecule diffuse into the cell?

LUCKY_DIMON [66]

Answer: Directly through the phospholipid membrane

Explanation:

The cell membrane consist of a phospholipid bilayers structure. In the interior of the membrane, the phospholipid tail are hydrophobic, which makes the cell membrane to be selectively permeable, it is permeable to non polar molecules and impermeable to polar molecules.

Because Steroids are fat soluble, non polar compounds, they can diffuse directly through the hydrophobic, non polar core of the phospholipid bilayer without the use of carrier proteins.

5 0

3 years ago

carbon disulfide is formed by the reaction of coke (carbon) with sulfur dioxide. how many moles of cs2 will be generated if 8.0

DerKrebs [107]

The balanced chemical reaction:

<span>5C + 2SO2 → CS2 + 4CO
</span>
We are given the amount of coke to be used for the reaction. This will be the starting point for the calculations.

8 mol C ( 1 mol CS2 / 5 mol C ) = 1.6 mol CS2

5 0

3 years ago

What did the name carbon come from

Simora [160]

<span>The English name carbon comes from the Latin carbo for coal and charcoal.</span>

5 0

3 years ago

Read 2 more answers

Kc for the reaction of hydrogen and iodine to produce hydrogen iodide.

tatiyna

Answer:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.025M$

Explanation:

Hello.

In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:

$2HI\rightleftharpoons H_2+I_2$

Whereas the law of mass action (equilibrium expression) is:

$Kc=\frac{[H_2][I_2]}{[HI]^2}$

That in terms of initial concentrations and reaction extent or change $x$ turns out:

$Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}$

And the solution via solver or quadratic equation is:

$x_1=0.183M\\\\x_2=0.210M$

Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.391M-2*0.183M=0.025M$

Regards.

6 0

3 years ago