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dybincka [34]
3 years ago
11

The pka of hco3 - (or pka2 of h2co3) is 10.33. what is the ph of a solution that has 0.1 m na2co3 and 1.0 m nahco3?

Chemistry
1 answer:
Margarita [4]3 years ago
4 0

The given solution is a mixture of NaHCO_{3}and Na_{2}CO_{3}. It acts as a buffer as it is a combination of the weak acid HCO_{3}^{-}and it's conjugate base CO_{3}^{2-}.

[Acid] = [HCO_{3}^{-}]=1.0 M

[Base] =[CO_{3}^{2-}]=0.1 M

pH of the buffer solution can be calculated from Hendersen-Hasselbalch equation as below:

pH=pK_{a}+log\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}

pH=10.33+log\frac{0.1}{1.0}

pH = 10.33+(-1)

     = 9.33


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2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2
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Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

                      Mg  +  O₂  ⇒  MgO

               Reactants    Elements    Products

                       1            Magnesium       1

                       2           Oxygen              1

Balanced chemical reaction

                      2Mg  +  O₂  ⇒  2MgO

              Reactants    Elements    Products

                       2           Magnesium       2

                       2           Oxygen             2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

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The electron transport process makes water and ATP and is sometimes called ________ because it requires oxygen. oxidation dephos
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The powder could be acetaminophen, analgesic  having chemical formula C_{17}H_{21}NO_{4}

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = \frac{mass}{molar \;mass}

Moles of carbon =\frac{67.31g}{12g/mole}

=5.60 moles

Moles of hydrogen = \frac{mass}{molar \;mass}

Moles of hydrogen = \frac{6.978 g}{1 g/mole}

=6.978 moles

Moles of nitrogen =\frac{mass}{molar \;mass}

Moles of nitrogen = \frac{4.617  g}{14 g/mole}

=0.329 moles

Moles of oxygen =\frac{mass}{molar \;mass}

Moles of oxygen =\frac{21.10 g}{16 g/mole}

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is C_{17}H_{21}NO_{4}.

Learn more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

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Can someone please help me
Bumek [7]
The answer is A. I think
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