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dybincka [34]
3 years ago
11

The pka of hco3 - (or pka2 of h2co3) is 10.33. what is the ph of a solution that has 0.1 m na2co3 and 1.0 m nahco3?

Chemistry
1 answer:
Margarita [4]3 years ago
4 0

The given solution is a mixture of NaHCO_{3}and Na_{2}CO_{3}. It acts as a buffer as it is a combination of the weak acid HCO_{3}^{-}and it's conjugate base CO_{3}^{2-}.

[Acid] = [HCO_{3}^{-}]=1.0 M

[Base] =[CO_{3}^{2-}]=0.1 M

pH of the buffer solution can be calculated from Hendersen-Hasselbalch equation as below:

pH=pK_{a}+log\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}

pH=10.33+log\frac{0.1}{1.0}

pH = 10.33+(-1)

     = 9.33


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<em><u>700N</u></em>

Explanation:

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<em><u>mass</u></em><em><u>=</u></em><em><u>35</u></em>

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6 0
3 years ago
What is the concentration of 60 mL of H3PO4 if it is neutralized by 225 mL of 2 M Ba(OH)2?
goldfiish [28.3K]

7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.

Explanation:

Data given:

volume of phosphoric acid, Vacid =60 ml

volume of barium hydroxide, Vbase = 225 ml

molarity of barium hydroxide, Mbase = 2M

Molarity of phosphoric acid, Macid =?

the formula for titration is used as:

Macid x Vacid = Mbase x Vbase

rearranging the equation to get Macid

Macid = \frac{Mbase x Vbase}{Vacid}

Macid =\frac{225 X 2}{60}

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the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.

8 0
3 years ago
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How do you solve this ??
kotegsom [21]
Answer : Option A) 2.00 eV

Explanation : The conversion of J to eV is done with the following formula;

E_{eV} = E_{J} X (6.241 X 10^{18})

Here, we have the value of particle in terms of Joules which is 3.2 X 10^{-19}

So, on substituting we get,
E_{eV} = 3.2 X 10^{-19}  X  (6.241 X 10^{18} )


E_{eV} = 1.99 eV so, it can be rounded off to 2.00 eV.
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Answer:

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4 0
2 years ago
True or false
Ivanshal [37]

Answer:

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4 0
3 years ago
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