Answer:
<em><u>700N</u></em>
Explanation:
<em><u>F</u></em><em><u>=</u></em><em><u>ma</u></em>
<em><u>mass</u></em><em><u>=</u></em><em><u>35</u></em>
<em><u>acceleration</u></em><em><u> </u></em><em><u>=</u></em><em><u>20</u></em>
7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.
Explanation:
Data given:
volume of phosphoric acid, Vacid =60 ml
volume of barium hydroxide, Vbase = 225 ml
molarity of barium hydroxide, Mbase = 2M
Molarity of phosphoric acid, Macid =?
the formula for titration is used as:
Macid x Vacid = Mbase x Vbase
rearranging the equation to get Macid
Macid = 
Macid =
Macid = 7.5 M
the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.
Answer :
Option A) 2.00 eV
Explanation : The conversion of J to eV is done with the following formula;

Here, we have the value of particle in terms of Joules which is 3.2 X

So, on substituting we get,

= 3.2 X

X


= 1.99 eV so, it can be rounded off to 2.00 eV.
Answer:
true because of the elements