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faltersainse [42]
3 years ago
13

Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b

ond? View Available Hint(s) Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent bond?
a.NaCl
b.Cl2
c.CO2
d.NH3
Chemistry
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl     This elements form an ionic bond, so this option is incorrect.

b.Cl2      Here there are two non metals  but the form one single covalent bond, so this option is incorrect.

c.CO2  Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

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marta [7]

Answer:

N=+2

O=-2

Explanation:

The compound NO is electrically neutral.

Lets assign the oxidation number of nitrogen to be N. The oxidation number of oxygen (-2) is then used as a reference.

For the compound to have a zero charge,  sum of the oxidation numbers equals zero.

N+ (-2)=0

N=+2

O=-2

7 0
3 years ago
How many electrons does an alpha particle contain
mihalych1998 [28]
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8 0
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For some hypothetical metal the equilibrium number of vacancies at 750°C is 2.8 × 1024 m−3. If the density and atomic weight of
mash [69]

Answer:

The correct answer is 5.447 × 10⁻⁵ vacancies per atom.

Explanation:

Based on the given question, the at 750 degree C the number of vacancies or Nv is 2.8 × 10²⁴ m⁻³. The density of the metal is 5.60 g/cm³ or 5.60 × 10⁶ g/m³. The atomic weight of the metal given is 65.6 gram per mole. In order to determine the fraction of vacancies, the formula to be used is,  

Fv = Nv/N------ (i)  

Here Nv is the number of vacancies and N is the number of atomic sites per unit volume. To find N, the formula to be used is,  

N = NA×P/A, here NA is the Avogadro's number, which is equivalent to 6.022 × 10²³ atoms per mol, P is the density and A is the atomic weight. Now putting the values we get,  

N = 6.022 × 10²³ atoms/mol × 5.60 × 10⁶ g/m³ / 65.6 g/mol

N = 5.14073 × 10²⁸ atoms/m³

Now putting the values of Nv and N in the equation (i) we get,  

Fv = 2.8 × 10²⁴ m⁻³ / 5.14073 × 10²⁸ atoms/m^3

Fv = 5.44669 × 10⁻⁵ vacancies per atom or 5.447 × 10⁻⁵ vacancies/atom.  

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Answer:

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Explanation:

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What intermolecular force involves non polar molecules
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www.ausetute.com.au/intermof.html


7 0
3 years ago
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