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soldi70 [24.7K]
2 years ago
12

Determine the enthalpy change when 23.5 g of carbon is reacted with oxygen according to the reaction C(s) + O2(g) CO2(g) delta H

= –394 kJ/mol
Chemistry
1 answer:
xeze [42]2 years ago
8 0
We are provided with the amount of energy released when one mole of carbon reacts. We mus first convert the given mass of carbon to moles and then compute the energy released for the given amount.

Moles = mass / atomic mass
Moles = 23.5 / 12
Moles = 1.96 moles


One mole releases 394 kJ/mol
1.96 moles will release:
394*1.96
= 772.24

The enthalpy change of the reaction will be -772.24 kJ
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Does substitution reactions cause haloalkanes?
ivanzaharov [21]

Answer:

No, that sort of reaction do not form named compounds.

Explanation:

6 0
3 years ago
Solid Iron (III) reacts with oxygen gas to form iron (III) oxide, which is the compound we see when rust is present. Based on th
Sunny_sXe [5.5K]

Answer:

Option E is correct. none of the above is correct

Explanation:

Step 1: Data given

Solid Iron (III) = Fe^3+

iron (III) oxide = Fe2O3

Molar mass Fe = 55.845 g/mol

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation:

4Fe + 3O2 → 2Fe2O3

4 moles of iron will need 2 moles of oxygen gas to fully react

⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react

B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.

⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3

C.9 moles of oxygen can produce 9 moles of Iron (III) oxide

⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3

D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.

⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3

E.none of the above

6 0
3 years ago
In a particular experiment, 2.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.
Neporo4naja [7]

Answer:

4.18 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given: For Li

Given mass = 2.50 g

Molar mass of Li  = 6.94 g/mol

<u>Moles of Li  = 2.50 g / 6.94 g/mol = 0.3602 moles</u>

Given: For N_2

Given mass = 2.50 g

Molar mass of N_2 = 28.02 g/mol

<u>Moles of N_2 = 2.50 g / 28.02 g/mol = 0.08924 moles</u>

According to the given reaction:

6Li+N_2\rightarrow 2Li_3N

6 moles of Li react with 1 mole of N_2

1 mole of Li react with 1/6 mole of N_2

0.3602 mole of Li react with \frac {1}{6}\times 0.3602 mole of N_2

Moles of N_2 that will react = 0.06 moles

Available moles of N_2 = 0.08924 moles

N_2 is in large excess. (0.08924 > 0.06)

Limiting reagent is the one which is present in small amount. Thus,

Li is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

6 moles of Li gives 2 mole of Li_3N

1 mole of Li gives 2/6 mole of Li_3N

0.3602 mole of Li react with \frac {2}{6}\times 0.3602 mole of Li_3N

Moles of Li_3N = 0.12

Molar mass of Li_3N = 34.83 g/mol

Mass of Li_3N = Moles × Molar mass = 0.12 × 34.83 g = 4.18 g

<u>Theoretical yield = 4.18 g</u>

5 0
3 years ago
Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. D-tagatose is sugar with six carbo
Bingel [31]

Answer:

Hexose category and ketohexose category

Explanation:

The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category

Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category

Attached below is the remaining part of the solution

6 0
3 years ago
What is the ph of a solution of 0.700 m kh2po4, potassium dihydrogen phosphate?
GalinKa [24]
Molal or molar? There is a difference
4 0
3 years ago
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