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1 year ago

What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?

1 answer:

4 0

The volume of 0. 250 mole sample of $H_{2}$ gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is 3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

P is the pressure of the hydrogen gas = 1.7 atm
Vis the volume of the hydrogen gas = ?
n is the number of the hydrogen gas = 0.25 mole
R is the universal gas constant = 0.082 atm L/mole K
T is the temperature of the sample = 35°C = 35 + 273 = 308 K

By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is 3.71 L.

learn more about ideal gas equation

brainly.com/question/4147359

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BigorU [14]

Answer:

False

Explanation:

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we can prove this with an example. Suppose we have an augmented matrix A for linear system with a row of zeros,

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3 years ago

Represent the formation of cations for the following metal atoms using electron dot structures. (a) Al (b) Sr (c) Ba

vagabundo [1.1K]

the formation of cations by using electron dot structures are :

a) Al

Al . losing the three valence electrons makes the Al³⁺

b) Sr :

Sr : losing the two valence electrons makes Sr²⁺

c) Ba

: Ba , losing the two valence electrons makes it Ba²⁺

A Lewis electron dot diagram is a representation of the valence electrons of an atom that employments specks around the image of the element. The number of dots equals the number of valence electrons within the molecule. These dots are arranged to the right and left and over and underneath the symbol, with no more than two dots on a side. Cations are the positive ions shaped by the loss of one or more electrons. The foremost commonly shaped cations of the representative elements are those that include the loss of all of the valence electrons.

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1 year ago

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Zolol [24]

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2 years ago

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sergejj [24]

Answer:

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3 years ago

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igor_vitrenko [27]

Answer:

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Explanation:

0.187 mol BaCl2 x $\frac{208 g}{1 mol}$

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3 years ago