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liq [111]
2 years ago
8

Explain how horizontal motion can be uniform while vertical motion is accelerated.

Physics
1 answer:
iren [92.7K]2 years ago
7 0
In projectile motion horizontal motion has zero acceleration and when there is no air resistance acting on the object the motion will be uniform. Motion in the vertical direction is accelerated downwards to to the acceleration due to gravity
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What would the weight of an astronaut be on Neptune if his mass is 68 kg and acceleration of gravity of Neptune is 11.15 m/s^2?
Dima020 [189]
Weight = Mass of object * Gravity of experimented place
Here, m = 68 Kg
g' = 11.15 m/s²

Substitute their values, 
w = 68 * 11.15
w = 758.2 N

In short, Your Answer would be 758.2 Newtons 

Hope this helps!
6 0
3 years ago
How do unbalanced forces acting on an object affect its motion when the object is at rest? What if it is moving?
Montano1993 [528]

Answer:

It pushes it because an unbalanced force is pushing more newtons than something that isn't even moving. Even if it is moving, it depends which side is pushing/pulling the most force.

Explanation:

4 0
3 years ago
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Plants release water vapor into the atmosphere through the process called _____.
timofeeve [1]
The process is called transpiration  <span />
6 0
3 years ago
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Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?
tester [92]

Answer: 40\ N/C

Explanation:

Given

Magnitude of charge is q=0.5\ C

Force experienced is F=20\ N

Electric field intensity is the electrostatic force per unit charge

\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C

Thus, the electric field intensity is 40\ N/C

6 0
3 years ago
An automobile of mass 2000 kg moving at 30 m/s is braked suddenly with a constant braking force of 10000 N. How far does the car
saveliy_v [14]

Answer:

The car traveled the distance before stopping is 90 m.

Explanation:

Given that,

Mass of automobile = 2000 kg

speed = 30 m/s

Braking force = 10000 N

For, The acceleration is

Using newton's formula

F = ma

Where, f = force

m= mass

a = acceleration

Put the value of F and m into the formula

-10000 =2000\times a

Negative sing shows the braking force.

It shows the direction of force is opposite of the motion.

a = -\dfrac{10000}{2000}

a=-5\ m/s^2

For the distance,

Using third equation of motion

v^2-u^2=2as

Where, v= final velocity

u = initial velocity

a = acceleration

s = stopping distance of car

Put the value in the equation

0-30^2=2\times(-5)\times s

s = 90\ m

Hence, The car traveled the distance before stopping is 90 m.

6 0
3 years ago
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