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Mkey [24]
4 years ago
15

WILL UPVOTE EVERY ANSWER! MULTIPLE CHOICE!

Physics
1 answer:
pav-90 [236]4 years ago
6 0
The pointer of an analog meter is connected to a "<span>coil suspended by bearings"

Hope this helps!</span>
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A DC motor's magnet has a magnetic field that ____ the wire loop's magnetic field, therefore causing the loop to rotate.
jek_recluse [69]

b. deflects. A DC motor's magnet has a magnetic field that <em><u>deflects</u></em> the wire loop's magnetic field, therefore causing the loop to rotate.

When a conductor, through which an electric current passes, is immersed in a magnetic field, it experiences a deflects force according to the Law of Lorentz creating as result that the loop rotate.

5 0
3 years ago
Read 2 more answers
शब्द के जिस रुप से उसके पुरुष जाति के होने का बोध होता है उसे कहते हैं?​
AVprozaik [17]

Answer:

A

Algebra For what values of the variables must ABCD be a parallelogram?

B

23. A 2y + 2 B 24. B

(3x + 10)

(8x + 5)º

3x + 6

54°

D

С

D

A

Зу - 9 с

ly+4

8 0
3 years ago
I need help understanding this concept . Would appreciate it so much. Thank you
Firlakuza [10]

Answer:

Explanation:

Both these questions are based on the Universal Law of Gravitation, which is given by :

F = Gm1m2 / r²

2) F = 6.67 x 10⁻¹¹ x 8 x 10³ x 1.5 x 10³ / 1.5 x 1.5

   F = 6.67 x 10⁻⁵ x 8 / 1.5

   F = 35.57 x 10⁻⁵ N

3) F = 6.67 x 10⁻¹¹ x 7.5 x 10⁵ x 9.2 x 10⁷ / 7.29 x 10⁴

   F = 6.67 x 10⁻³ x 7.5 x 9.2 / 7.29

   F = 63.13 x 10⁻³ N

7 0
3 years ago
What is work?
WITCHER [35]
It’s applying force to move an object
5 0
3 years ago
A polarized light that has an intensity I0 = 52.0 W/m² is incident on four polarizing disks whose planes are parallel and center
IceJOKER [234]

Answer:

The transmitted intensity through all polarizers = 34.73

Explanation:

Given :

Incident intensity = 52 W/m^2

Angle between the transmission axis and polarizer optic axis = 18°

According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.

∴ I = I' cos^2\alpha

Where I= transmitted intensity, I'= incident intensity, \alpha = angle between the transmission axis and polarizer optic axis.

Here, there are four polarizing disks so that.

from first disk,

∴ I₁ = 52 (cos)^2 18°

       = 52×0.904

       = 47.01

Now I₁  behave as an incident light for second polarizer so we only multiply

cos^218 term

so we write,

∴ I₂ = 47.01×0.904

      = 42.495

From third polarizer,

∴ I₃ = 42.495×0.904

       = 38.415

From forth polarizer,

∴ I₄ = 38.415×0.904

       = 34.73

Therefor, the the transmitted intensity through forth polarizer = 34.73 W/m^2.

5 0
3 years ago
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