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Anna [14]
3 years ago
13

Identify the intermolecular forces present in each of these substances ch4

Chemistry
2 answers:
djverab [1.8K]3 years ago
7 0
There are four type of intermolecular forces: ionic, dipole-dipole, hydrogen bonds and London disperssion forces.

CH4 have  no ions, so there are  not ionic forces.

CH4 is a symetrical molecule, so there cannot be a net dipole in the molecule, so there is not dipole-dipole interaction.

Hydrogen bonding is only possbile when H is bonded to N, O or F, beacuse they are the atoms that considerable higher electgronegativy than hydrogen.

So, the only intermolecular force present in CH4 molecules is London disperssion forces, which is a force present in any molecule and is the weakiest one. That explains the low melting and boiling points of CH4. 
melamori03 [73]3 years ago
3 0

Since ch4 is a non-polar particle it isn't equipped for hydrogen holding or dipole-intermolecular powers. The main intermolecular powers in ch4 are London scattering powers. The major intermolecular powers would be dipole-powers and London scattering powers.  

Further Explanation:  

Ch4:  

CH4 represents Methane, Natural Gas (science; carbon iota encompassed by 4 hydrogen iotas) Suggest new definition. This definition shows up every now and again and is found in the accompanying Acronym Finder classifications: Science, prescription, designing, and so on.  

ch4 a dipole power:

Just one of them, NO, has a changeless electric dipole minute thus it is the main particle which can have dipole-intermolecular communications; NO will have a higher breaking point than either Ar or CH4. The main non-evaporating intermolecular communication on account of Ar and CH4 is a London scattering association.  

Intermolecular powers:  

Intermolecular powers are the powers which intercede association between particles, including powers of fascination or shock which act among particles and different sorts of neighboring particles, e.g., iotas or particles.  

causes intermolecular powers:

Intermolecular powers are electrostatic in nature and incorporate van der Waals forcesand hydrogen securities. Particles in fluids are held to different atoms by intermolecular cooperations, which are flimsier than the intramolecular associations that hold the iotas together inside particles and polyatomic particles.

Subject: chemistry

Level: High School

Keywords: Ch4, ch4 a dipole power, Intermolecular powers, causes intermolecular powers.

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Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

4 0
2 years ago
Mitosis is an example of what
Phantasy [73]

Answer:

mitosis is Exampel of cell divison

Explanation:

mitosis is the second stage of cell divison or somatic cell divison

3 0
3 years ago
A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
3 years ago
PLEASE HELP! ONLY SERIOUS ANSWERS! I APPRECIATE ANYTHING!! 30PTS!!!
xenn [34]
1 is b 2 is a 3 is d 4 is a 5 is c
5 0
3 years ago
Which one of the following is not a property of a base?
AlekseyPX

Answer:

option B is correct

Explanation:

5 0
3 years ago
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