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Anna [14]
3 years ago
13

Identify the intermolecular forces present in each of these substances ch4

Chemistry
2 answers:
djverab [1.8K]3 years ago
7 0
There are four type of intermolecular forces: ionic, dipole-dipole, hydrogen bonds and London disperssion forces.

CH4 have  no ions, so there are  not ionic forces.

CH4 is a symetrical molecule, so there cannot be a net dipole in the molecule, so there is not dipole-dipole interaction.

Hydrogen bonding is only possbile when H is bonded to N, O or F, beacuse they are the atoms that considerable higher electgronegativy than hydrogen.

So, the only intermolecular force present in CH4 molecules is London disperssion forces, which is a force present in any molecule and is the weakiest one. That explains the low melting and boiling points of CH4. 
melamori03 [73]3 years ago
3 0

Since ch4 is a non-polar particle it isn't equipped for hydrogen holding or dipole-intermolecular powers. The main intermolecular powers in ch4 are London scattering powers. The major intermolecular powers would be dipole-powers and London scattering powers.  

Further Explanation:  

Ch4:  

CH4 represents Methane, Natural Gas (science; carbon iota encompassed by 4 hydrogen iotas) Suggest new definition. This definition shows up every now and again and is found in the accompanying Acronym Finder classifications: Science, prescription, designing, and so on.  

ch4 a dipole power:

Just one of them, NO, has a changeless electric dipole minute thus it is the main particle which can have dipole-intermolecular communications; NO will have a higher breaking point than either Ar or CH4. The main non-evaporating intermolecular communication on account of Ar and CH4 is a London scattering association.  

Intermolecular powers:  

Intermolecular powers are the powers which intercede association between particles, including powers of fascination or shock which act among particles and different sorts of neighboring particles, e.g., iotas or particles.  

causes intermolecular powers:

Intermolecular powers are electrostatic in nature and incorporate van der Waals forcesand hydrogen securities. Particles in fluids are held to different atoms by intermolecular cooperations, which are flimsier than the intramolecular associations that hold the iotas together inside particles and polyatomic particles.

Subject: chemistry

Level: High School

Keywords: Ch4, ch4 a dipole power, Intermolecular powers, causes intermolecular powers.

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Molecular and empirical formulas
shepuryov [24]

Answer:

See below

Explanation:

Molecular formula  ( just write down all of the elements )   C 4 H4 O4

Empiracle formual    CHO

"Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound"

7 0
2 years ago
Find the volume of 1760 grams of copper
klio [65]

Answer:

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3 years ago
Use the following equation to answer the questions below:
Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

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What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

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3 0
3 years ago
The density of gold is 19.3 g /cm cubed The density of iron pyrite is 5.0 g /cm cubed. Is a nugget of iron pyrite and a nugget o
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V_{gold} = \frac{m}{\rho} = \frac{50\ g}{19.3\ g/cm^3} = \bf 2.59\ cm^3

V_{iron} = \frac{m}{\rho} = \frac{50\ g}{5.0\ g/cm^3} = \bf 10\ cm^3
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