Answer:
Mass = 53.45 g
Explanation:
Given data:
Mass of propane = 200 g
Mass of S₂ = 75 g
Theoretical yield /Mass of CS₂ = ?
Solution:
Balanced Chemical equation:
C₃H₈ + 5S₂ → 4H₂S + 3CS₂
Number of moles of propane:
Number of moles = mass / molar mass
Number of moles = 200 g/ 44.1 g/mol
Number of moles = 4.54 mol
Number of moles of S₂:
Number of moles = mass / molar mass
Number of moles = 75 g/ 64.14 g/mol
Number of moles = 1.17 mol
Now we will compare the moles of carbon disulfide with both reactant.
S₂ : CS₂
5 : 3
1.17 : 3/5×1.17 = 0.702
C₃H₈ : CS₂
1 : 3
4.54 : 3×4.54 = 13.62 mol
Number of moles of CS₂ produced by S₂ are less so it will limiting reactant and limit the yield of carbon disulfide.
Theoretical yield of carbon disulfide.
Mass = number of moles ×molar mass
Mass = 0.702 mol × 76.14 g/mol
Mass = 53.45 g
Answer: Please see answer below
Explanation:
Mecury vapor lamp is better to use than Sodium vapor light, this is because because
---The Filaments of the lamp in sodium emit fast moving electrons, which causes valence electrons of the sodium atoms to excite to higher energy levels which when electrons after being excited, relax by emitting yellow light which concentrates on the the monochromatic bright yellow part of the visible spectrum which is about 580-590 or about (589nm) which will fall incident on the calibrations making it difficult to see
While
In Mercury vapor lamp, The emitted electrons from the filaments, after having been excited by high voltage, hit the mercury atoms but the excited electrons of mercury atoms relax and emits an ultraviolet uv invisible lights falling on the mecury vapour lamp to produce white light covering a wide range of (380-780 nm) which is visible that is why it is used for calibrations purposes in lightening applications.
Because their molecules are more tightly packed. Massdensity = ---------- Volume
So more densely packed molecules means more mass per unit volume. Hence metals are denser than non-metals.
<span>A. Exact ecological footprints are often difficult to calculate, but estimates can be useful in comparing populations.
</span>Which of the following could be said about ecological footprints? <u /> <u>Exact ecological footprints are often difficult to calculate, but estimates can be useful in comparing populations.</u><u />
NOT:
b. Ecological footprints can't be used to determine carrying capacity.
C. Ecological footprints don't take into account resources needed to absorb and manage wastes.
<span>D. The average ecological footprints for various countries are nearly identical.</span>
